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3 years ago

Lazy works at mc he gets paid 7.25 a hour, he works 5 days a week and 8 hours a day. How much will his check come out too?

Mathematics

2 answers:

Simora [160]3 years ago

8 0

That depends how how long he pay period is. For 5 days of work, he will make $290. Hope that helps.

olchik [2.2K]3 years ago

6 0

7.25 dollars an hour x 8 hours x 5 days =

Answer: $290 every week

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3x-1=-10 what is x and can you please show how you figured out what x is?

umka21 [38]

Answer:

x= -3

Step-by-step explanation:

3x-1= -10

+1 +1

3x=-9 = -3

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2 years ago

How to show my work when I have a math problem

Over [174]

Answer:

Here is how

Step-by-step explanation:

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2 years ago

Members of the swim team want to wash their hair. The bathroom has less than 5600 liters of water and at most 2.5 liters of sham

nordsb [41]

Answer:

Yes, the bathroom has enough water and shampoo for all of them.

Step-by-step explanation:

70L+ 60S < 5600

Putting 8 into L and 7 into S, gives:

70(8) + 60(7) = 560 + 420 = 980

That is definitely less than 5600, so water is OK.

Now,

0.02L + 0.01S

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Hence, bathroom has enough water and shampoo for them.

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2 years ago

Read 2 more answers

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Svetradugi [14.3K]

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2 years ago

Please calculate this limit please help me

Tasya [4]

Answer:

We want to find:

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}$

Here we can use Stirling's approximation, which says that for large values of n, we get:

$n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n$

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}$

Now we can just simplify this, so we get:

$\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\$

And we can rewrite it as:

$\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}$

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

$\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}$

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2 years ago