Check the picture below.
so, assuming d1 and d2 are the diagonals of it, bearing in mind that the diagonals of a rhombus bisect each, cut in equal halves, then we can get the area of one of those 4 congruent triangles in the rhombus, notice each triangle has a base of 6 and a height of 10.
Answer:
12z−32
Step-by-step explanation:
Distribute:
=(−4)(z)+(−4)(3)+(−4)(5)+(−4)(−4z)
=−4z+−12+−20+16z
Combine Like Terms:
=−4z+−12+−20+16z
=(−4z+16z)+(−12+−20)
=12z+−32
4x+32
4 goes into 4 1 time. (4/4=1)
4 goes into 32 8 times. (32/4=8)
We can factor out 4 from both numbers.
4(1x+8)
aka 4(x+8)
Step-by-step explanation:
I'm pretty sure that the answer is B 81.5%
Answer:
72 units
Step-by-step explanation:
arc length= 48π
Radius: R
48π = 2 * π * R * 120/360
R = 72