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2 years ago

Torri had

Mathematics

1 answer:

tiny-mole [99]2 years ago

5 0

Answer:

yes .

Step-by-step explanation:

yes because the 7 percent is less than 2 dollars (1.4) , so her 20 dollars will be enough .

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First 100 terms of the following sequence 3 ,7 ,11

Sveta_85 [38]

Given that $a_1 = 3, d = 4$

<u>Find the nth term:
</u>
$a_n = 3 + 4(n - 1)$

$a_n = 3 + 4n - 4$

$a_n = 4n - 1$

<u>Find the 100th term:</u>

$a_{100} = 4(100) - 1 = 399$

<u>Find the Sum:</u>

$\text{Sum} = 100(\dfrac{a_1 + a_{100}}{2} )= 100 (\dfrac{3 + 399}{2}) = 20100$

7 0

4 years ago

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$470 is raised by 30%. What is the value after the increase?

alekssr [168]

<h3>Answer: $611</h3>

Work Shown:

30% of 470 = 0.30*470 = 141

The value goes up by $141, so the answer would be 470+141 = $611

A slight shortcut would be to say

1.30*470 = 611

This works because 1.30 = 1 + 0.30 = 100% + 30%

3 0

3 years ago

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Match each triangle with its classification

Julli [10]

A obtuse isosceles b obtuse scalene c acute isosceles

5 0

3 years ago

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two pages that are back to back in a text have 201as the sum of their page numbers what are the page numbers.

REY [17]

Answer:

Pages 100 and 101

Step-by-step explanation:

Round 201 to 200 (to make it easier).

Divide 200 by 2, because it is 2 pages.

You are left with 100.

100 is one of the pages, but because you rounded down 1 number, the other number must be 101, because the pages are back to back.

I hope this made sense, this is just how I figured it out. :)

6 0

4 years ago

Alice, Benjamin, and Carol each try independently to win a carnival game. If their individual probabilities for success are 1/5,

kicyunya [14]

Answer:

E. 7/40

Step-by-step explanation:

The following probabilities are given:

P (Alice Wins) = 1/5

P (Benj. Wins) = 3/8

P (Carol Wins) = 2/7

We can deduce the probabilities for losses:

P (Alice Loses) = 1 - P (Alice Wins) = 1 - 1/5 =4/5

P (Benj. Loses) = 1 - P (Benj. Wins) = 1 - 3/8 = 5/8

P (Carol Loses) = 1 - P (Carol Wins) = 1 - 2/7 =5/7

The possible outcomes that two players win and one player loses are as follows:

Alice Wins, Benj Wins, Carol Loses

Alice Loses, Benj Wins, Carol Wins

Alice Wins, Benj Loses, Carol Wins

We can compute the probabilities of each of the 3 outcomes above:

P(Alice Wins, Benj Wins, Carol Loses) = (1/5) x (3/8) x (5/7) = 3/56

Alice Loses, Benj Wins, Carol Wins = (4/5) x (3/8) x (2/7) = 3/35

Alice Wins, Benj Loses, Carol Wins = (1/5) x (5/8) x (2/7) = 2/56

P ( 2 wins and 1 loss)

= 3/56 + 3/35 + 2/56

= 343 / 1960

= 7/40

7 0

3 years ago

Read 2 more answers