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3 years ago

Can anyone help me please

Mathematics

1 answer:

Zolol [24]3 years ago

6 0

$\sf (6x^2-6x-4)-(5x^2-8x-4)$

Distribute -1 in the 2nd parenthesis:

$\sf 6x^2-6x-4-5x^2+8x+4$

Combine like terms:

$\sf 6x^2-5x^2=x^2$

$\sf -6x+8x=2x$

$\sf -4+4=0$

So we have:

$\sf x^2+2x$

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write the equation of a line that passes through (4,10) and is parallel to the line with the equation y=-3x+7

Alex_Xolod [135]

Y-20=1/3(x-4)

y = 1/3x+56/3

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4 years ago

There were 3,000 persons at the football game.

wel

If you divide by two then the answer would be 1.500 tickets that were sold at the game.

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4 years ago

A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of zinfandel, 10 of merlot, and 12 of cabe

e-lub [12.9K]

Answer:

Step-by-step explanation:

From the given information:

The total number of wine = 9 + 10 + 12 = 31

(1)

The number of distinct sequences used for serving any five wines can be estimated by using the permutation of the number of total wines with the number of wines served.

i.e

= $^{31}P_5$

$=\dfrac{31!}{(31-5)!}$

$=\dfrac{31!}{(26)!}$

$=\dfrac{31\times 30\times 29\times 28\times 27\times 26!}{(26)!}$

= 20389320

(2)

If the first two wines served = zinfandel and the last three is either merlot or cabernet;

Then, the no of ways we can achieve this is:

= $^9P_2\times ^{22}P_3$

$= \dfrac{9!}{(9-2)!}\times \dfrac{22!}{(22-3)!}$

$= \dfrac{9!}{(7)!}\times \dfrac{22!}{(19)!}$

$= \dfrac{9*8*7!}{(7)!}\times \dfrac{22*21*20*19!}{(19)!}$

= 665280

(3)

The probability that no zinfandel is served is computed as follows:

Total wines (with zinfandel exclusion) = 31 - 9 = 22

Now;

the required probability is:

$= \dfrac{^{22}P_5 }{^{31}P_5}$

$= \dfrac{\dfrac{22!}{(22-5)!} } {\dfrac{31!}{(31-5)!} }$

$= \dfrac{\dfrac{22!}{17!} } {\dfrac{31!}{(26)! }}$

$= \dfrac{(\dfrac{22*21*20*19*18*17!}{17!})} {(\dfrac{31*30*29*28*27*26!}{(26)! })}$

= 0.1549

≅ 0.155

4 0

3 years ago

Create a factorable polynomial with a GCF of 5z. Rewrite that polynomial in two other equivalent forms. Explain how each form wa

Mekhanik [1.2K]

Answer with explanation:

It is given that, G C F of two polynomials is 5 z.

We have to Write that two polynomials.

A=5 z² + 5 z =5× z× (z+1)

B=10 z + 5 z²=5×z×(z+2)

→→G C F ,of A and B=5 z

Now, writing polynomials in equivalent form

1.5 z² + 5 z =5× z× (z+1)=(z+1)×z×5=5 z + z²

2. 10 z + 5 z²=5×z×(z+2)=(z+2)×z×5=5 z² + 10 z

to write in equivalent form of above polynomials, we have used commutative property of addition ,and Multiplication ,which states that, A+B=B +A, and AB=BA.

And, Distributive property of multiplication with respect to addition and Subtraction.

1. A × (B +C)=A × B + A × C

2. A × (B -C)=A × B - A × C

3 0

3 years ago

Give me 3 equivalent fractions for 10/30

Elis [28]

Answer:

1/3, 100/300, 20/60

Step-by-step explanation:

Just multiply or divide the numerator and denominator with the same number.

Hope this helps you :)

6 0

3 years ago