Question

I am just clueless!!!!!

Answer 1

Answer:

6 units

Step-by-step explanation:

use the distance formula to find the new length of JK, which is J'K'

d = $\sqrt{(y-y)^2+(x-x)^2}$

coordinates of J: (-7,3)

coordinates of J': (-7/2, 3/2)

coordinates of K: (3/2, -3/2)

d = $\sqrt{(-3/2-3/2)^2+(3/2-(-3/2)^2}$

d = $\sqrt{(-6/2)^2+(-10/2)^2}$

d = $\sqrt{3^2+5^2}$

d = $\sqrt{36}$

d = 6