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Deffense [45]
3 years ago
5

I am just clueless!!!!!

Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

6 units

Step-by-step explanation:

use the distance formula to find the new length of JK, which is J'K'

d = \sqrt{(y-y)^2+(x-x)^2}

coordinates of J: (-7,3)

coordinates of J': (-7/2, 3/2)

coordinates of K: (3/2, -3/2)

d = \sqrt{(-3/2-3/2)^2+(3/2-(-3/2)^2}

d = \sqrt{(-6/2)^2+(-10/2)^2}

d = \sqrt{3^2+5^2}

d = \sqrt{36}

d = 6

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\huge\text{Hey there!}

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~\frak{Amphitrite1040:)}

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