1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Verizon [17]
3 years ago
7

Log(x+4)=8 Please help I don’t understand it I will give brainliest

Mathematics
1 answer:
irakobra [83]3 years ago
4 0
The answer should be 2
You might be interested in
What is the value of the expression below when a is 3, b is 25, and c is 5?
aleksklad [387]

Answer:

es el 17 por que es no el 97

6 0
1 year ago
Read 2 more answers
How long is a school bus
Sonja [21]

Answer:

45 ft

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which line segments in the diagram below are parallel?
AveGali [126]
The answer is B due to the corresponding 130
8 0
2 years ago
An equilateral triangle can have angles that each measure 68° true or false
grandymaker [24]
FALSE! Any 3 angles of any triangle add up to 180 degrees. An equilateral triangle's angles should each be 60 degrees.
3 0
2 years ago
Read 2 more answers
Im finally on the brainliest board and its my birthday today and what is 47 X 47 X 47 =???
jonny [76]
Congratulations! It's 103,823
8 0
2 years ago
Read 2 more answers
Other questions:
  • Do you know what 3.3 to the second power is?
    9·2 answers
  • What is the answer to this 4×3^2?<br><br>Evaluate the expression. ​
    13·2 answers
  • All of them plz I need help if ur older Shouldnt be hard
    14·1 answer
  • Simplify the expression 5/x^-2y^5
    11·1 answer
  • PLEASS HHELPPPP
    12·1 answer
  • Express as fraction in simplest form
    13·1 answer
  • Solve for y: 5y = 9 1/2
    14·2 answers
  • Help me plsss....
    13·2 answers
  • Someone can help me ?
    10·1 answer
  • Which is an equivalent form of the expression 1800(1.2)^-t
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!