2 years ago

4(2v+6)=[?]v+[ ]what is the questionmark

Mathematics

1 answer:

IrinaVladis [17]2 years ago

5 0

8 because we multiply 4by 2

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Collection of domestic animals is a set. However, a collection of big domestic animal is not a set. How do you justify this stat

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Collection of domestic animals is a set. However, a collection of big domestic animal is not a set as it is a subset.

<h3>What are Domesticated animals?</h3>

Domestic animals are known to bee dogs, cats, etc. that can live along with humans.

Note that Collection of domestic animals is a set but the collection of big domestic animal is a subset of domestic animals this is because the big domestic animal are part of the domestic animals and as such it will be a subset.

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A certain virus infects one in every 200 people. a test used to detect the virus in a person is positive 70% of the time when t

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We're told that

$P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995$

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a. We want to find $P(A\mid B)$ . By definition of conditional probability,

$P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}$

By the law of total probability,

$P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)$

Then

$P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657$

(the first equality is Bayes' theorem)

b. We want to find $P(A^C\mid B^C)$ .

$P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984$

since $P(B^C\mid A^C)=1-P(B\mid A^C)$ .

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2 years ago

Powers of products and quotients. simplify (7y^4)^2

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The answer simplified is 49y^8

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Answer:

(1,400)

Step-by-step explanation:

Hope this helps

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