The inequality 
can be used to find the domain of 
Answer: Option B
<u>Step-by-step explanation:</u>
We have , domain is the set of all possible x-values which will make the function "work", and will output real y-values. Basically to find domain of any function means to find range of values of x that will give real values of y.
For the equation , we know that there's no value ( iota or complex numbers are there but here we will deal with real numbers ) of negative numbers under square root
∴
must be greater than or equal to 0.
⇒
Answer:
y = (x + 1)(x - 0.586) ( x - 3.414)
Step-by-step explanation:
I sure wouldn't recommend doing this by trial and error.
I made a graph of which you can see. Every time this monster touches the x axis and speeds away upward is two equal roots of y. So the square root would be one of each of them.
y = (x + 1)^2 (x - 0.586)^2 (x - 3.414)^2
are the listed roots.
The square root is
y = (x + 1)(x - 0.586) ( x - 3.414)
Do I know that this is right? I don't. But I can tell you this: if you multiply 1^2 * (-0.586)^2 * (- 3.414)^2
you get 4 just as you should. Amazing that we have tools that do that sort of thing.
Answer:
Step-by-step explanation:
\[2~ sin^2 x+3sin x+1=0\]
\[2sin^2x+2sin x+sin x+1=0\]
2sinx(sin x+1)+1(sin x+1)=0
(sin x+1)(2 sin x+1)=0
either sin x+1=0
sin x=-1=sin 3π/2=sin (2nπ+3π/2)
x=2nπ+3π/2,where n is an integer.
or 2sin x+1=0
sin x=-1/2=-sin π/6=sin (π+π/6),sin (2π-π/6)=sin (2nπ+7π/6),sin (2nπ+11π/6)
x=2nπ+7π/6,2nπ+11π/6,
where n is an integer.
Answer: 6
Step-by-step explanation:
because i said so
Answer:
C
Step-by-step explanation:
In general for arithmetic sequences, recursive formulas are of the form
aₙ = aₙ₋₁ + d,
and the explicit formula (like tₙ in your problem), are of the form
aₙ = a₁ + (n - 1)d,
where d is the common difference. So converting between the two of these isn't so bad. In this case, your problem wants you to have an idea of what t₁ is (well, every answer says it's -5, so there you are) and what tₙ₊₁ is. Using the formulas above and your given tₙ = -5 + (n - 1)78, we can see that the common difference is 78, so no matter what we get ourselves into, the constant being added on at the end should be 78. That automatically throws out answer choice D.
But to narrow it down between the rest of them, you want to use the general form for the recursive formula and substitute (n + 1) for every instance of n. This will let you find tₙ₊₁ to match the requirements of your answer choices. So
tₙ₊₁ = t₍ₙ₊₁₎₋₁ + d ... Simplify the subscript
tₙ₊₁ = tₙ + d
Therefore, your formula for tₙ₊₁ = tₙ + 78, which is answer choice C.
