B. congruent, im pretty sure
Answer:
132 in^2 but DOUBLE CHECK MY WORK!!!!
Step-by-step explanation:
Break it down into parts ok. So I see a 10x10 square, two 2x4 right triangles and a 4x6 rectangle.
10x10 is 100 in
1/2(2*4) = 4 x 2 = 8 in
6x4 = 24 in
add them together to get 132 in^2
Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
(5.59241)(10)^6 *Possible Answer*
