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kogti [31]
3 years ago
7

Identify the values of the variables. Give your answers in simplest radical form. HELP ASAP!!

Mathematics
2 answers:
kumpel [21]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Since the triangle is right use the sine/ tangent ratios to solve for x and y

note sin60° = \frac{\sqrt{3} }{2} and tan60° = \sqrt{3}

sin60° = \frac{opposite}{hypotenuse} = \frac{3\sqrt{6} }{y}

ysin60° = 3\sqrt{6}

y × \frac{\sqrt{3} }{2} = 3\sqrt{6}

multiply both sides by 2 and divide by \sqrt{3}

y v= 6\sqrt{\frac{6}{3} } = 6\sqrt{2}

tan60° = \frac{opposite}{adjacent} = \frac{3\sqrt{6} }{x}

xtan60° = 3\sqrt{6}

x × \sqrt{3} = 3\sqrt{6}

divide both sides by \sqrt{3}

x = 3\sqrt{\frac{6}{3} } = 3\sqrt{2}


MariettaO [177]3 years ago
8 0
First, put 3(sqrt(6)) in a different form:
sqrt(9) * sqrt(6) = sqrt(54)

We know that a 30 60 90 triangle has a horizontal leg equal to 1, a vertical leg equal to sqrt(3), and a hypotenuse equal to 2.

Find a multiplier/ratio with this information:
(sqrt(54))/(sqrt(3)) = sqrt(18)
given value/accepted value = multiplier

Now, multiply the other values by the multiplier:
1*sqrt(18) = sqrt(18) or 3(sqrt(2))
2*sqrt(18) = 2(sqrt(18)) or 6(sqrt(2))

Your answer would be:
x = 3(sqrt(2))
y = 6(sqrt(2))
Or option b.

If you don’t understand any part of my work, please feel free to comment with a question on this answer. :)
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Which values are possible rational roots of 4x3+9x2−x+10=0 according to the rational root theorem? Select each correct answer. ±
navik [9.2K]

ANSWER


The possible rational roots are:


\pm\frac{1}{2},\pm2,\pm \frac{5}{2}


EXPLANATION


According to the rational root theorem, the possible rational roots of the polynomial,



4x^3+9x^2-x+10=0


are all the possible factors of the constant term divided by all the possible factors of the coefficient of the highest degree of the polynomial.



Therefore we examine the numerator and denominator of the options provided to see if they are factors of 10 and 4 respectively.



For

\pm\frac{1}{2}, we can see that 1 is a factor of 10 and 2 is a factor of 4, hence it is a possible rational root.


The same thing applies to \pm2,\pm \frac{5}{2} also.


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\pm \frac{2}{5}, 2 is a factor of 10 but 5 is not a factor of 2, hence it is not a possible rational root.


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3 years ago
The drama club is printing T-shirts for its members. The printing company charges a certain amount for each shirt plus set up fe
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Answer: $7

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