F(x)=x^2-3x+15 find f(-8)
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Given :
As a plane takes off it ascends at a 20 degree angle of elevation.
If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.
To Find :
How high is the plane after 10 seconds.
Solution :
Distance travelled by plane, D = 2900 ft.
Angle of elevation, Ф = 20°.
Height gained is given by :
H = 2900 × sin 20°
H = 991.86 ft.
Therefore, height of plane after 10 seconds is 991.86 ft.
Hence, this is the required solution.