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3 years ago

Please help with this

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

7 0

Answer:

option D is the ans

Step-by-step explanation:

option d is the right ans

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dangina [55]

Hi. Here it is!
I hope this help!

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3 years ago

Help me out I can’t figure out how to do this

serious [3.7K]

Check the picture below.

$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{1}{4} \end{cases}\implies V=\cfrac{4\pi \left( \frac{1}{4} \right)^3}{3}\implies V=\cfrac{4\pi\frac{1}{64}}{3} \\\\\\ V=\cfrac{\frac{4\pi}{64}}{3}\implies V=\cfrac{\frac{\pi}{16}}{\frac{3}{1}}\implies V=\cfrac{\pi }{16}\cdot \cfrac{1}{3}\implies V=\cfrac{\pi }{48}\implies \stackrel{\textit{rounded up}}{V=0.07}$

4 0

4 years ago

What is the correct answer

Over [174]

Answer:

cột số 2

Step-by-step explanation:

8 0

3 years ago

SUppose the total cost C(x) to manufacture a quantity x of insecticide (in hundreds of liters) is given by

Hitman42 [59]

Answer:

a) $C(x)$ is increasing in two regions: (i) $(+\infty, 8\,s)$ and (ii) $(10\,s,+\infty)$ .

b) $C(x)$ decreases in $(8\,s, 10\,s)$ .

Step-by-step explanation:

Let $C(x) = x^{3}-27\cdot x^{2}+240\cdot x +850$ , where $x$ is the quantity of insecticide, measured in hundreds of liters, and $C(x)$ is the total manufacturing cost as a function of the quantity of the insecticide, measured in US dollars. A possible approach to determine which regions of $C(x)$ are decreasing and increasing by means of the first derivative and graphing tools. The first derivative of the function is:

$C'(x) = 3\cdot x^{2}-54\cdot x+240$ (1)

Please notice that regions where C(x) is increasing has $C'(x) > 0$ , whereas $C'(x) < 0$ when $C(x) < 0$ .

We notice that $C(x)$ is increasing in two regions: (i) $(+\infty, 8\,s)$ and (ii) $(10\,s,+\infty)$ . Besides, $C(x)$ decreases in $(8\,s, 10\,s)$ .

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3 years ago

Condense: log x + log y

Drupady [299]

Answer:

log(xy)

Step-by-step explanation:

Do notice that this only works when the bases of the logs are the same

written in exponent form, this rule is : a^x * a^y = a^(x+y)

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4 years ago