Example (not a very likely example, however):
At 11 pm the temperature is -15 degrees F, and it continues to drop by 10 degrees F every hour.
Answer:
50%
Step-by-step explanation:
Total students = 12 + 18 + 6 = 36
Seventh-graders = 18
18/36*100 = 50%
Answer:
c: is the answer 2 (3 x + 4) (x + 2)
Step-by-step explanation:
Factor the following:
6 x^2 + 20 x + 16
Factor 2 out of 6 x^2 + 20 x + 16:
2 (3 x^2 + 10 x + 8)
Factor the quadratic 3 x^2 + 10 x + 8. The coefficient of x^2 is 3 and the constant term is 8. The product of 3 and 8 is 24. The factors of 24 which sum to 10 are 4 and 6. So 3 x^2 + 10 x + 8 = 3 x^2 + 6 x + 4 x + 8 = 2 (3 x + 4) + x (3 x + 4):
2 2 (3 x + 4) + x (3 x + 4)
Factor 3 x + 4 from 2 (3 x + 4) + x (3 x + 4):
Answer: 2 (3 x + 4) (x + 2)
Answer:
12.5
Step-by-step explanation:
25/8 x 8/5 x 5/2 simplify 25 by 5
5/8 x 8/1 x 5/2 simplify 8 by 8
5/1 x 1/1 x 5/2
5 x 1 x 5/2
5 x 5/2
25/2
12.5
Answer:
C). sign chart; zeroes
Step-by-step explanation:
A function potentially changes sign at each of its <em>zeros</em> and vertical asymptotes. So, to fill out a <em>sign chart</em>, you need to determine what the sign is on either side of each of these points. You can do that using test numbers, or you can do it by understanding the nature of the zero or asymptote.
<u>Examples:</u>
f1(x) = (x -3) . . . . changes sign at the zero x=3. Is positive for x > 3, negative for x < 3.
f2(x) = (x -4)^2 . . . . does not change sign at the zero x=4. It is positive for any x ≠ 4. This will be true for any even-degree binomial factor.
f3(x) = 1/(x+2) . . . . has a vertical asymptote at x=-2. It changes sign there because the denominator changes sign there.
f4(x) = 1/(x+3)^2 . . . . has a vertical asymptote at x=-3. It does not change sign there because the denominator is of even degree and does not change sign there.
