Theres 30 kilograms of 10% apple juice. How many kilograms of apples does it need to increase the current apple juice to 25%?
1 answer:
The mass of the apple juice needed to increase the initial concentration to 25% is 45 kg
The given parameters;
- <em>Mass of the apple juice, m = 30 kg</em>
- <em>current percentage, = 10%</em>
- <em>final percent after increment = 25%</em>
Let the mass added to increase the percentage to 30% = x
10% ----------------- 30 kg
25% ------------------ ?
The additional mass is calculated as;
Thus, the mass of the apple juice needed to increase the initial concentration to 25% is 45 kg.
Learn more about percentage and ratio here: brainly.com/question/11752721
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<span>The correct answer is $1452.50 per year.
Explanation:<span>
We use the formula
</span></span>![P(1+\frac{r}{n})^{nt}+PMT(\frac{[(1+\frac{r}{n})^{nt}-1]}{\frac{r}{n}})\times (1+\frac{r}{n})](https://tex.z-dn.net/?f=P%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D%2BPMT%28%5Cfrac%7B%5B%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D-1%5D%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D%29%5Ctimes%20%281%2B%5Cfrac%7Br%7D%7Bn%7D%29)
,<span><span>
where P is the amount of principal invested, r is the interest rate as a decimal number, n is the number of times per year the interest is compounded, PMT is the monthly deposit added, and t is the number of years.
Since the amount of principal is not stated, we will assume that Bob is depositing the same amount every following year as he does the first year, so we will let PMT=P.
Our interest rate, r, is 4.2%; 4.2%=4.2/100=0.042.
The number of times the interest is compounded annually, n, is 1.
The amount of time, t, is 7.
We know he wants $50,000. This gives us the equation
50000=P(1+0.042/1)</span></span>⁽¹ˣ⁷⁾<span><span>+P{[(1+0.042/1)</span></span>⁽¹ˣ⁷⁾<span><span>]/(0.042/1)}*(1+0.042/1).
Simplifying this a bit, we have
50000=P(1.042)</span></span>⁷<span><span>+P((1.042</span></span>⁷<span><span>)/0.042)*(1.042).
We can factor out P, giving us
50000=P[1.042</span></span>⁷<span><span>+((1.042</span></span>⁷<span><span>)/0.042)*1.042].
This then gives us
50000=P(34.4234).
Divide both sides:
50000/34.4234 = (P(34.4234))/34.4234,
which gives us P=1452.50.</span></span>
Explanation:<span>
We use the formula
</span></span>
where P is the amount of principal invested, r is the interest rate as a decimal number, n is the number of times per year the interest is compounded, PMT is the monthly deposit added, and t is the number of years.
Since the amount of principal is not stated, we will assume that Bob is depositing the same amount every following year as he does the first year, so we will let PMT=P.
Our interest rate, r, is 4.2%; 4.2%=4.2/100=0.042.
The number of times the interest is compounded annually, n, is 1.
The amount of time, t, is 7.
We know he wants $50,000. This gives us the equation
50000=P(1+0.042/1)</span></span>⁽¹ˣ⁷⁾<span><span>+P{[(1+0.042/1)</span></span>⁽¹ˣ⁷⁾<span><span>]/(0.042/1)}*(1+0.042/1).
Simplifying this a bit, we have
50000=P(1.042)</span></span>⁷<span><span>+P((1.042</span></span>⁷<span><span>)/0.042)*(1.042).
We can factor out P, giving us
50000=P[1.042</span></span>⁷<span><span>+((1.042</span></span>⁷<span><span>)/0.042)*1.042].
This then gives us
50000=P(34.4234).
Divide both sides:
50000/34.4234 = (P(34.4234))/34.4234,
which gives us P=1452.50.</span></span>