4000 that's a weird one
<span />
Answer:
see explanation
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = 
and (a, b) = (3, - 2) , thus
y - (- 2) = (x - 3) , that is
y + 2 = ( x - 3) ← in point- slope form
(b)
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = , thus
y = x + c ← is the partial equation
To find c substitute (3, - 2) into the partial equation
- 2 = 
+ c ⇒ c = - 2 - = - 
y = x - ← in slope- intercept form
The intent of the construction appears to be to produce tangents from point P to the circle O. There are several possible next steps:
• Name the point of intersection just created between the arc and circle O
• Draw a line (or segment) between points P and J
• Draw a line (or segment) between point P and the intersecting point just created on circle O.
Hello from MrBillDoesMath!
Answer: x = 1
Discussion
:
Per the author, the equation to solve is 12 = 5x + 7
Isolate the "x" variable by subtracting 7 from both sides of the equation:
12 = 5x + 7
-7 = -7
---------------------
12-7 = 5x + 0
or
5 = 5x
Dividing both sides by 5 gives x - 1
Regards, MrB
Answer:
0=0
1=10
2=15
3=20
Step-by-step explanation:
What I did was I multiplied each number by 5, then added 5.
