The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <=
W <=
cm
Answer:
D) y = 27 · (3)^x
Step-by-step explanation:
Replace x with the x values.
27 · (3)^-2 = 27 · 1/9 = 3
27 · (3)^-1 = 27 · 1/3 = 9
27 · (3)^0 = 27 · 1 = 27
27 · (3)^1 = 27 · 3 = 81
17 · (3)^2 = 27 · 9 = 243
D is your answer.
Hope this helps
Answer:
<h3>It's answer is D. 11 </h3>
Here we can see there is modulus so
while doing calculation
| -3-8 |
| -11 |
Here it is modulus so - changes into +
so it's answer is 11.
Given:
Diameter of outer circle = 20 inches.
We need to find the Area of the outer circle to get the radius of the inner circle.
Area = πr²
Outer circle Area = 3.14 * (10in)² = 314 in²
314 in² * 64% probability = 200.96 in² Area of the inner circle.
200.96 in² = 3.14 * r²
200.96 in² / 3.14 = r²
64 in² = r²
√64 in² = √r²
8 in = r
radius of inner circle is 8 inches.
Answer:
2
Step-by-step explanation:
