The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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The first one is 12.5%
the second one is .18
Answer:
x = 3
Step-by-step explanation:
8x -6 = 18
Add 6 to both sides.
8x = 24
Divide both sides by 8 to isolate x.
x = 3
Hey there!
Linear functions have a continuous change.
Let's check these tables and see if we can tell linear functions from non-linear functions.
The first one is
- we add 1 each time
- we subtract 3 each time

Let's try the next one:
- we add 1 each time
- we add 5 each time

Let's try the third one:
- x values: -1, 0, 1, 2
- - we add 1 each time
- we add 3, then 2, then 1..
So this table doesn't represent a linear function.
Let's check the fourth one:
- we add 1 each time
- we add 1 each time
Thus, Option C is the right option.
Hope everything is clear.
Let me know if you have any questions!
Always remember: Knowledge is power!
30
6 times 5 is 30 and since its 6 per hour you just do it to five :)