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Sedaia [141]
4 years ago
8

If ƒ (x ) = 2x 2 + 3, find ƒ (3). A.31 B.15 C.21 D.39

Mathematics
2 answers:
Shkiper50 [21]4 years ago
5 0
Just plug in what x equals, as they tell you.

f(x) = 2x² + 3     f(3)

f(3) = 2(3²) + 3
f(3) = 2(9) + 3
f(3) = 18 + 3
f(3) = 21

c. 21 is your answer

hope this helps, God bless!
nlexa [21]4 years ago
3 0
F(3)=2*3²+3=18=3=21
C is the answer
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Rewrite the function y = x^2 - 6x + 14 in vertex form, y = (x - h)^2 + k.
Mila [183]

the equation of a parabola in

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¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

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∣

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−−−−−−−−−−−−−−−−−−−−−


where

(

h

,

k

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to obtain this form

complete the square


y

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4

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x

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16

−

16

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⇒

y

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(

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in vertex form


⇒

vertex

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4

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to obtain the intercepts


∙

let x = 0, in the equation for y-intercept


∙

let y = 0, in the equation for x-intercept


x

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0

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y

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14

=

14

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y-intercept


y

=

0

⇒

(

x

+

4

)

2

−

2

=

0

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add 2 to both sides


⇒

(

x

+

4

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2

=

2


take the square root of both sides


√

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x

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4

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2

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±

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note plus or minus


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x

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±

√

2

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subtract 4 from both sides


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exact values

graph{(y-x^2-8x-14)((x+4)^2+(y+2)^2-0.04)=0 [-10, 10, -5, 5]}

3 0
3 years ago
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Shalnov [3]

Point C(0,3) is the y intercept because it's where x=0


4 0
3 years ago
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How to solve ×+6y=13. 2×+y=15
saul85 [17]

Answer:

x, y = 7, 1

Step-by-step explanation:

x+6y=13 ............ (i)

2x+y=15 ........... (ii)

We will apply substitute method.

From equation (i), we can get,

x+6y=13

or, x = 13 - 6y .......... (iii)

Putting the value of x in equation (ii), we can get,

2x+y=15

or, 2 × (13 - 6y) + y = 15

or, 26 - 12 y + y = 15 [multiplying]

or, -11 y = 15 - 26 [Subtracting 26 from both the sides]

or, -11 y = -11

or, [(-11 y) ÷ (-11)] = [(-11) ÷ (-11)] [Dividing both the sides by -11]

or, y = 1

Therefore, the value of y = 1

Putting y = 1 in equation (iii), we get,

x = 13 - 6y

or, x = 13 - 6 × 1

or, x = 13 - 6

or, x = 7

Therefore, the value of x = 7.

Answer: x, y = 7, 1

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kari74 [83]

The number line M-N is from 0 - 9.

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6 is the coord 2/3 across the numberline from 0 to 9.

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