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3 years ago

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In the polynomial below, what number should replace the question mark to produce a difference of squares?

1 answer:

Stella [2.4K]3 years ago

3 0

A polynomial is an algebraic equation that consists of more than one term. Otherwise, it is called a monomial. The technique in producing a difference of the squares is completing of the squares method. For a quadratic formula with a general form of ax2 + bx + c = 0, you can determine c such that the formula could be factored into two monomials. The equation would be (b/2)^2.

For example, if the equation is x^2 + 2x+ __ = 0, c is solved as follows:

c = (2/2)^2 = 1

The equation would be x^2 + 2x +1 = 0. When you simplify and factor it out, the equation would become (x+1)^2 = 0.

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The slope of a line is 58, and the line passes through the point (−8,−4).

nadezda [96]

Answer:

y=58x+460

Step-by-step explanation:

y=mx+b

We are given m=58 so we have

y=58x+b

We are given (-8,-4) is a point on the line.

-4=58(-8)+b

-4=-464+b

460=b

So the line in slope intercept form is y=58x+460

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3 years ago

Simplify 27 to the negative 2 thirds power. 9 1 over 9 negative 1 over 9 −9

zimovet [89]

Answer:

The answer is 1/9 ⇒ the second answer

Step-by-step explanation:

* In the exponential functions we have some rules

(1) b^(-m) = 1/(b^m) (for all nonzero real numbers b)

- If we have negative power we reciprocal the base

to get positive power

(2) (b^m)^n = b^(mn)

- If we have power over power we multiply them

* In our problem: $(27)^{-\frac{2}{3}}$

- At first change 27 to b^n

∵ 27 = 3 × 3 × 3 = 3³

∴ $27^{-\frac{2}{3}}=(3^{3})^{-\frac{2}{3}}$

* Lets use rule (2)

∴ $27^{-\frac{2}{3}}=3^{-2}$ ⇒ 3 × -2/3 = -2

* Use rule (1)

∴ $3^{-2}=\frac{1}{3^{2}}=\frac{1}{9}$ ⇒ reciprocal the fraction to change the sig of the power

* The answer is 1/9

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brilliants [131]

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