Question

What is an equation in slope-intercept form for the line (-5, 2) and (5,-3)?​

Answer 1

Answer:

y = $-\frac{1}{2} x$ $-\frac{1}{2}$

Step-by-step explanation:

solved using point-slope form

points given: (-5, 2) and (5, -3)

slope: $\frac{-3-2}{5-(-5)} =\frac{-5}{10} =-\frac{1}{2}$

y = $-\frac{1}{2}$ x + b

insert x- and y- values of (-5, 2) and solve for b

2 = $-\frac{1}{2}$ (-5) + b

2 = 2.5 + b

subtract 2.5 from both sides

2 - 2.5 = 2.5 + b - 2.5

-0.5 = b

insert b- value

y = $-\frac{1}{2} x$ $-\frac{1}{2}$