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yKpoI14uk [10]
2 years ago
9

Regular price: $225.75 Precent of discount: 30%

Mathematics
1 answer:
erastovalidia [21]2 years ago
4 0

Answer:

$156.63

Step-by-step explanation:

223.75 - (223.75 x .3) = 156.625

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8n - (2n+11 - 54)<br>simplify
Serjik [45]

Answer:

8n - (2n + 11 - 54) =

Step-by-step explanation:

6n + 43, I used a calculator !

5 0
3 years ago
Will Give Brainliest, Answer ASAP m∠O = <br> m∠N =
irina1246 [14]

Answer:

∠ O = 61°, ∠ N = 119°

Step-by-step explanation:

In a parallelogram

Consecutive angles are supplementary

Opposite angles are congruent, thus

x + 2x - 3 = 180

3x - 3 = 180 ( add 3 to both sides )

3x = 183 ( divide both sides by 3 )

x = 61°

Thus

∠ O = ∠ M = x = 61°

∠ N = ∠ P = 2x - 3 = 2(61) - 3 = 122 - 3 = 119°

6 0
4 years ago
Please hurry i need this fast
andrey2020 [161]

Answer:

9

Step-by-step explanation:

Hope this helps! Have a nice day! Please consider making me Brainliest!

6 0
4 years ago
A teacher has a bag of candy. If she gives every student in her class 4 pieces of candy, she is left with 48 pieces of candy. Ho
yawa3891 [41]
Well you can't actually find a number, but you can make an equation.
lets call the bag of candy x, and the number of students in the teachers class S.

she gives every student in her class 4 pieces, so to find that amount, we have to multiply the number of students in her class by 4, the pieces of candy. 4S

afterwards she has 48 pieces, which is the endpoint, x is the starting point because that's the amount of candy the teacher started with.

so your equation is x-4S=48, but the thing is, the question is looking for the amount of students she gave candy to, so we have to isolate S, or in easier words; put S on one side, and the numbers on the other.

so the equation is S=1/4x-12

6 0
3 years ago
Please help me<br> Show your work
GrogVix [38]

<u>ANSWER TO PART A</u>

The given triangle has vertices J(-4,1), K(-4,-2),L(-3,-1)


The mapping for rotation through 90\degree counterclockwise has the mapping


(x,y)\rightarrow (-y,x)


Therefore

J(-4,1)\rightarrow J'(-1,-4)


K(-4,-2)\rightarrow K'(2,-4)


L(-3,-1)\rightarrow L'(1,-3)


We plot all this point and connect them with straight lines.


ANSWER TO PART B


For a reflection across the y-axis we negate the x coordinates.


The mapping is



(x,y)\rightarrow (-x,y)


Therefore

J(-4,1)\rightarrow J''(4,1)


K(-4,-2)\rightarrow K''(4,-2)


L(-3,-1)\rightarrow L''(3,-1)


We plot all this point and connect them with straight lines.


See graph in attachment







7 0
3 years ago
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