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1 year ago

What's the expression for the given value of the variable. 3x+5 when x=5

Mathematics

1 answer:

Pepsi [2]1 year ago

8 0

1) Let's evaluate that expression

3x+5

2) Since the value of x has been given, then let's plug that into the expression

3x+5

3(5) +5

15 +5

3) The answer is 20

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The midpoint of AB is (1.2). The coordinates of A are (-3, 6) Find the coordinates of B.

Gala2k [10]

Answer: coordinates of B are (5,-2)

Step-by-step explanation:

let B be (x2,y2)

x1 = -3 y1 = 6

x = 1

y = 2

x = (x2 + x1)/2

1 = (x2+(-3))/2

or, 2 = x2 - 3

so, x2 = 5

now

y = (y2+y1)/2

or, 2 = (y2 + 6)/2

or, 4 = y2 + 6

so, y2 = -2

3 0

2 years ago

HELP PLZ ASAP WORTH XTRA POINTS!! INCLUDES SCREENSHOT

Rainbow [258]

Answer:

Step-by-step explanation:

8x-13+7x-17=180( because stright angle = 180 degree)

15x-30=180

15x=210

x=14

8(14)-13= 99

4 0

3 years ago

Do. Had an album that holds 900 photos. Each page of albums holds 9 photos. If 37% of the album is empty, how many pages are fil

Xelga [282]

Answer:

63 pages are filled with photos.

Step-by-step explanation:

900 photos with 9 photos a page 900/9=100

100 pages

37% of 100 is 37

100-37 is 63

7 0

2 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

Square root of 214 show work thanks

Nataliya [291]

√214= 14.6287388383278

Calculator maybe??

6 0

3 years ago