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2 years ago

1/4 * k ^ 5 - 3k ^ 3 + k ^ 2 - k for k = 2

Mathematics

1 answer:

eimsori [14]2 years ago

7 0

Answer:

-14

Step-by-step explanation:

(1/4)2⁵-3×2³+2²-2

=(1/4)32-3×8+4-2

=(32/4)-24+4-2

8-24+4-2

=-14

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In a right triangle, the hypotenuse has endpoints P(–3, 2) and Q(1, –3). On a coordinate plane, line P Q has points (negative 3,

mrs_skeptik [129]

Answer:

The length of PR is 5 units

Step-by-step explanation:

Here, we want to calculate the length of PR

Since PQ is the hypotenuse, it means that the right-angle would be between lines PR and RQ

Also, since R is on the third quadrant, then its coordinates are (-x,-y)

To get the coordinates of R since we know that we need a right angle, we drop a straight vertical line through P and a straight horizontal line through Q

What this mean is that the coordinates of R will take the x-coordinate of the point P and the y-coordinate of the point Q

Hence, we have that the coordinates of the point R is (-3,-3)

Now, we want to calculate the length of PR

PR will be the distance between the points P and R

Mathematically, to get this, we use the distance formula

That will be;

√(y2-y1)^2 + (x2-x1)^2

Thus, we have

√(2-(-3)^2 + (-3-(-3))^2

= √5^2 + 0^2

= √25 = 5 units

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DedPeter [7]

Answer:

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Step-by-step explanation:

Given as , for regular hexagonal pyramid :

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Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

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