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Zanzabum
3 years ago
6

kwesi is putting on sunscreen. he uses 3 ml to cover 45 cm squared of his skin. he wants to know how many milliliters of sunscre

en (g) he needs to cover 240 cm squared of his skin. he assumes the relationship between milliliters of sunscreen and area is properational.
Mathematics
2 answers:
Anastasy [175]3 years ago
6 0
Kwesi needs 16 ml of sunscreen.
cluponka [151]3 years ago
3 0

Answer:

16 milliliters of sunscreen (g) he needs to cover 240 cm squared of his skin

Step-by-step explanation:

He assumed that relationship between milliliters of sunscreen and area is proportional.

V\propto S

\frac{V_1}{S_1}=\frac{V_2}{S_2}=constant

Volume of sun screen used to cover45 cm^2,V_1= 3 mL

S_1=45 cm^2

Volume of sunscreen require to cover 240 cm^2 of skin will be=V_2

S_2=240 cm^2

\frac{V_1}{S_1}=\frac{V_2}{S_2}

\frac{3 mL}{45 cm^2}=\frac{V_2}{240 cm^2}

V_2=16 mL

16 milliliters of sunscreen (g) he needs to cover 240 cm squared of his skin.

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Wittaler [7]

Answer:

Time in which both companies charge same cost = 1.5 hour

Step-by-step explanation:

Given:

                                                        Fixed    Variable

Premier Landscaping charges          $15        $55

Ace Landscaping charges                               $65

Find:

Time in which both companies charge same cost:

Computation:

Assume in X time both companies charge same cost:

So,

Premier Landscaping total cost = Ace Landscaping total cost

⇒ $15 + $55(Time taken) = $65 (Time taken)

⇒ $15 = $65 (Time taken) - $55(Time taken)

⇒ $15 = $10 (Time taken)

⇒ Time taken = 1.5 hour

Time in which both companies charge same cost = 1.5 hour

6 0
3 years ago
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

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Find the angle theta in radians.<br> ( PLEASE SHOW STEPS )
yKpoI14uk [10]
Hello!

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Now we multiply by 2.5

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Note that the angle we see is obtuse, or greater than 90°.

Therefore, ∠<span>θ</span>≈143.25°

Now we need to convert this back into radians. This can be represented by the equation below.

\frac{ \pi }{180}x

First we divide pi by 180 then multiply by our angle.

\pi/180(143.25)≈2.5

Therefore, our angle theta is about 2.5 radians.

I hope this helps!
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