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3 years ago

What is 12 inches to 36 inches in percent of change?

Mathematics

2 answers:

NARA [144]3 years ago

8 0

%change=100(final-initial)/initial

You can plug in your values...if you meant initial=12 and final=36...

%change=100(36-12)/12=200%

Since it is positive, that is a 200% increase.

shtirl [24]3 years ago

6 0

Answer:

12 inches to 36 inches is a 300% increase

Step-by-step explanation:

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George had $6,000 in a savings account earning simple interest at a rate of 5% per year. At the end of the year, George paid 25%

Readme [11.4K]

Answer:

$225

Step-by-step explanation:

Given that:

Principal = $6,000

Interest rate = 5%

Time = 1 year

Taxes paid = 25% on the interest earned

To find:

Money earned after paying taxes ?

Solution:

First of all, let us calculate the total interest earned:

Formula for Simple Interest is given as:

$SI =\dfrac{PRT}{100}$

Where P is the principal

R is the rate of interest

T is the time taken

Putting the given values:

$SI =\dfrac{6000 \times 5\times 1}{100} =\$300$

Now, it is given that 25% of the interest earned is given as taxes.

Taxes paid = 25% of $300

$\Rightarrow \dfrac{25}{100} \times 300 =\$75$

Therefore, the money earned = Interest earned - Taxes paid

The money earned = $300 - $75 = $225

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3 years ago

chegg Y=4X−2 XX has a PDF of f_X(x)=\begin{cases} 3e^{-3x} & 0 \leq x \\ 0 & \text{otherwise}\end{cases}f X (x)={ 3e −

Licemer1 [7]

$\Bbb E[Y^2] = \Bbb E[(4X - 2)^2]$

so by definition of expectation,

$\Bbb E[Y^2] = \displaystyle \int_{-\infty}^\infty (4x-2)^2 f_X(x) \, dx = \int_0^\infty 3(4x-2)^2 e^{-3x} \, dx$

Integrate by parts (twice).

$\displaystyle \int_a^b u\,dv = uv\bigg|_a^b - \int_a^b v\,du$

First, let

$u = (4x-2)^2 \implies du = 8(4x-2)\,dx \\\\ dv = 3e^{-3x} \, dx \implies v = -e^{-3x}$

so that

$\displaystyle \Bbb E[Y^2] = -(4x-2)^2 e^{-3x} \bigg|_{x=0}^{x\to\infty} + 8 \int_0^\infty (4x-2) e^{-3x} \, dx \\\\ ~~~~ = 4 + 8 \int_0^\infty (4x-2) e^{-3x} \, dx$

Next,

$u = 4x-2 \implies du = 4\,dx \\\\ dv = e^{-3x} \, dx \implies v = -\dfrac13 e^{-3x}$

so that

$\displaystyle \Bbb E[Y^2] = 4 + 8 \left(-\frac13 (4x-2) e^{-3x} \bigg|_{x=0}^{x\to\infty} + \frac43 \int_0^\infty e^{-3x} \, dx\right) \\\\ ~~~~ = 4 + 8 \left(-\frac23 - \frac49 e^{-3x}\bigg|_{x=0}^{x\to\infty}\right) \\\\ ~~~~ = 4 - \frac{16}3 + \frac{32}9 = \boxed{\frac{20}9}$

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2 years ago

This means that √31 is between

Serggg [28]

5 and 6 (5 being the square root of 25 and 6 being the square root of 36, which are the closest perfect squares)

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3 years ago

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navik [9.2K]

9514 1404 393

Answer:

y < -1/4x -1

Step-by-step explanation:

The boundary line appears to go through the points (-4, 0) and (0, -1). This tells you it has a "rise" of -1 for a "run" of 4. The slope is ...

m = rise/run = -1/4

The y-intercept (b) is the point where the y-axis is crossed. The slope-intercept equation of the boundary line is ...

y = mx + b

y = -1/4x -1

The boundary line is dashed, so is not included in the solution set. The shading is below the line, so all y-values less than (but not equal to) the boundary line are in the solution set:

y < -1/4x -1

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3 years ago

How do you add integers with different sgns

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