11 1/3 since sunday’s total lemonade sold is 10 2/3 + 3 1/3 = 14 you subtract 2 2/3 from 14 which equals 11 1/3
Given :
In the early spring, the trout at Big Blue Lake swim at a depth of 30 feet below sea level.
When the lake warms up in the summer, the trout swim 20 feet deeper than that , d = 20 feet .
To Find :
At what position relative to sea level do the trout swim in the summer.
Solution :
Depth in spring from surface , .
Let , depth in summer is D .
Now , depth in summer relative to sea-level is :
Therefore , trout swim 50 feet deep below the sea level in the summer .
Hence , this is the required solution .
The point-slope form:
We have:
Substitute:
Answer: C. y - 5 = 3(x + 1)