Find the length of the diameter of a circle with the circumfance=62.8 cm.

IM SOO CONFUSEDD help???

lozanna [386]

Answer:

D.

Step-by-step explanation:

To tell whether the domains can include 0, all you need to do is find where x = 0, and whether the y-value is real.

h(x) = sqrt(2x^2 + 5x - 3)

= sqrt(0^2 + 5 * 0 - 3)

= sqrt(-3)

Since this includes the square root of a negative number, h(0) is an imaginary number. That means that we can eliminate choices A and B.

If you look at the graph of w(x), when x = 0, there is a real value for the y-value on the graph. But, if you think about it, if you have 0 workers, there is no way that you can still be producing wrenches. So, the domain cannot contain 0.

Your answer will be D.

Hope this helps!!

3 0

3 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

3 0

2 years ago

Me podrian ayudar en esto porfavor

Vilka [71]

Answer:

desafortunadamente no hablo español jajaja aunque lo estoy hablando bien no voy a ayudar solo quiero puntos gratis

Step-by-step explanation:

4 0

2 years ago

17 in long 1.3 ft wide and 8in high what is the volume

OverLord2011 [107]

Answer:

135.2

Step-by-step explanation:

Volume is LWH and that is 17 * 1.3 * 8=135.2

5 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST

stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, $\text { distance travelled }=\text { speed } \times \text { time }$

For air force plane $\rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }$

$\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }$

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, $159 \times \text { time taken by air force plane }=207 \times 5.3$

$\Rightarrow =\frac{207 \times 5.3}{159}$

$\Rightarrow =\frac{1097.1}{159}$

Time taken by air force plane = 6.9 hrs

6 0

3 years ago