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2 years ago

Being a part of an organization or giving back to the community is which rewards of work factor?

Computers and Technology

1 answer:

natima [27]2 years ago

5 0

The answer is option 2 that is "benefits" and the further discussion can be defined as follows:

The voluntary work and return to your community are far more than complying with school obligations.
The experience is incredibly rewarding and life-changing for some people who think you have to be rich or give back a lot of time.
This could not be more true, however, you don't have to be charged by the incentive you need is rendering to the community sometimes means uniting people and cooperating on the same cause.
The Local organizations or citizens can organize large-scale fundraising activities rather than donating individual financing and revenues, which increase awareness of the local need, support local unity, and contribute a great deal of money.

The wrong choice explanation can be defined as follows:

In choice 1, it is wrong because it is used as an official relationship to something.
In choice 3, it is wrong because this can be anything in the organization.
In choice 4, it is wrong because it stands for total cash.

Therefore the "Benefits" is the correct choice.

Learn more:

brainly.com/question/24530751

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Write a statement to create a Google Guava Multimap instance which contains student ids as keys and the associated values are st

Sergeu [11.5K]

Answer: provided in the explanation section

Explanation:

Note: take note for indentation so as to prevent error.

So we import com.google.common.collect.Multimap;

import java.util.Collection;

import java.util.Map;

class Main {

public static void main(String[] args) {

// key as studentId and List of Profile as value.

Multimap<String,Profile> multimap = ArrayListMultimap.create();

multimap.put("id1", new ExamProfile("examStudentId1"));

multimap.put("id1", new ELearningProfile("userId1"));

multimap.put("id2", new ExamProfile("examStudentId2"));

multimap.put("id2", new ELearningProfile("userId2"));

// print the data now.

for (Map.Entry<String, Collection<Profile>> entry : multimap.entrySet()) {

String key = entry.getKey();

Collection<String> value = multimap.get(key);

System.out.println(key + ":" + value);

}

// assuming String as the studentId.

// assuming Profile as the interface. And Profile can multiple implementations that would be

// specific to student.

interface Profile {

}

class ExamProfile implements Profile {

private String examStudentId;

public ExamProfile(String examStudentId) {

this.examStudentId = examStudentId;

}

class ELearningProfile implements Profile {

private String userId;

public ELearningProfile(String userId) {

this.userId = userId;

}

This code is able to iterate through all entries in the Google Guava multimap and display all the students name in the associated students profile.

8 0

3 years ago

Write a function listLengthOfAllWords which takes in an array of words (strings), and returns an array of numbers representing t

vesna_86 [32]

Answer:

public static int[] listLengthOfAllWords(String [] wordArray){

int[] intArray = new int[wordArray.length];

for (int i=0; i<intArray.length; i++){

int lenOfWord = wordArray[i].length();

intArray[i]=lenOfWord;

}

return intArray;

}

Explanation:

Declare the method to return an array of ints and accept an array of string as a parameter
within the method declare an array of integers with same length as the string array received as a parameter.
Iterate using for loop over the array of string and extract the length of each word using this statement int lenOfWord = wordArray[i].length();
Assign the length of each word in the String array to the new Integer array with this statement intArray[i]=lenOfWord;
Return the Integer Array

A Complete Java program with a call to the method is given below

import java.util.Arrays;

import java.util.Scanner;

public class ANot {

public static void main(String[] args) {

String []wordArray = {"John", "James", "David", "Peter", "Davidson"};

System.out.println(Arrays.toString(listLengthOfAllWords(wordArray)));

}

public static int[] listLengthOfAllWords(String [] wordArray){

int[] intArray = new int[wordArray.length];

for (int i=0; i<wordArray.length; i++){

int lenOfWord = wordArray[i].length();

intArray[i]=lenOfWord;

}

return intArray;

}

}

This program gives the following array as output: [4, 5, 5, 5, 8]

7 0

3 years ago

How many answers do you need to be able to write messages on here??

Kipish [7]

1,000

Hope this helps!

~Courtney

3 0

2 years ago

When an ethernet nic has been configured by os to use half-duplex, the transmit pair of the twisted-pair cable uses?

Maurinko [17]

Simplex, simplex, and half duplex.

Hope this helps!!

8 0

3 years ago

Determine whether or not the following pairs of predicates are unifiable. If they are, give the most-general unifier and show th

Evgen [1.6K]

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)

=> P(f(A), A, g(A)), P(f(A), A, g(A))

Thus , mgu = {x/y, z/y , y/A }.

Explanation:

Unification: Any substitution that makes two expressions equal is called a unifier.

a) P(B,A,B), P(x,y,z)

Use { x/B}

=> P(B,A,B) , P(B,y,z)

Now use {y/A}

=> P(B,A,B) , P(B,A,z)

Now, use {z/B}

=> P(B,A,B) , P(B,A,B}

Hence, most general unifier = {x/B , y/A , z/B }

b. P(x,x), Q(A,A)

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q

c. Older(Father(y),y), Older(Father(x),John)

Use {y/x}

=> Older(Father(x),x), Older(Father(x),John)

Now use { x/John }

=> Older(Father(John), John), Older(Father(John), John)

Thus , mgu ={ y/x , x/John }

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

Use { y/x }

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))

This is not unifiable as x cannot be bound for both A and B

e) P(f(x), x, g(x)), P(f(y), A, z)

Use {x/y}

=> P(f(y), y, g(y)), P(f(y), A, z)

Now use {z/g(y)}

P(f(y), y, g(y)), P(f(y), A, g(y))

Now use {y/A}

=> P(f(A), A, g(A)), P(f(A), A, g(A))

Thus , mgu = {x/y, z/y , y/A }.

7 0

3 years ago