The longest possible integer length of the third side of the triangle is 6 < x < 28
The sum of any two sides must be greater than the third side for a triangle to exist
let the third side be x
x + 11 > 17 and x + 17 > 11 and 11 + 17 > x
x > 6 and x > - 6 and x < 28
The longest possible integer length of the third side of the triangle is 6 < x < 28
The length of the 3 sides of a triangle needs to always be among (however no longer the same) the sum and the difference of the opposite two sides. As an example, take the instance of two, 6, and seven. and. consequently, the third side period should be extra than 4 and less than 8.
Learn more about triangles here: brainly.com/question/1675117
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a=future amount
p=present amount
r=rate in decimal
n=number off time per year compouonded
t=time in years
P=45,050
r=0.07001
n=4
t=1.25



A=49132.8798
round
A=$49,132.88
Answer:
1) 
2) 
3) 
4) 
Step-by-step explanation:
1) Since the whole angle is
, and to find the other angle, which is labeled as
, you subtract
from
:


2) Since you already have two angle measures
and
, you add them up and subtract it from
to get the angle measure for
:



3) Same thing from number 1. Subtract
from
:


4) Same thing from number 2. Add
and
and subtract it from
:



Answer:
600
3-4 months
Step-by-step explanation:
9514 1404 393
Answer:
- b = 757.7 m
- A = 17.2°
- C = 14.3°
Step-by-step explanation:
From the law of cosines, you can find the length of side b to be ...
b = √(a² +c² -2ac·cos(B))
b = √(184041 +128164 -307164cos(148.5°)) ≈ √574105.36
b ≈ 757.7
__
From the law of sines, you can find the measure of angle C to be ...
C = arcsin(c/b·sin(B))
C ≈ arcsin(358/757.7·sin(148.5°)) ≈ arcsin(0.246872)
C ≈ 14.3°
A = 180° -148.5° -14.3°
A = 17.2°
_____
Some graphing calculators have built-in triangle-solving functions. Apps are available for the purpose for phone or tablet. The screenshot shows a web site that does a nice job of solving the triangle.