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3 years ago

11

A TV has a listed price of $771.95 before tax. If the sales tax rate is 9.25%, find the total cost of the TV with sales tax incl

uded. Round your answer to the nearest cent, as necessary.

1 answer:

mel-nik [20]3 years ago

3 0

Answer:

$843.36

Step-by-step explanation:

:))

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X to the power of 3 - 7x + 6 factorise please whole step by step

Over [174]

Answer:

$(x + 3)(x - 2)(x - 1)$

Step-by-step explanation:

${x}^{3} - 7x + 6$

Factor using Rational Root Theorem.

This means our possible roots are

positve or negative (1,2,3,6). If we try positve 1, it is indeed a root.

This means that

$(x - 1)$

is a root.

We can divide the top equation by the root (x-1). Our new equation is

$( {x}^{2} + x - 6)$

Now we can factor this completely

$(x + 3)(x - 2)$

So this equation in factored form is

$(x + 3)(x - 2)(x - 1)$

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3 years ago

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Misha Larkins [42]

Answer:

2

Step-by-step explanation:

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3 years ago

Find the exact value of cos(sin^-1(-5/13))

son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

$\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}$

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}$

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

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3 years ago

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-Dominant- [34]

Answer:

Bottom left

Step-by-step explanation:

If you graph out the coordinates it goes in a perfect line, thus being linear.

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