The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
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Answer:
~ 15 %
Step-by-step explanation:
116.4 - 98.3 = 18.1
18.1 / 17.5 = 1.034 SD ABOVE the mean
this is a z-score of .8485 meaning 84.85 % have a score LESS than 116.4 so 15.15 % have a score higher
Answer:
6
Step-by-step explanation:
there