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jolli1 [7]
3 years ago
15

A bag contains only red and blue marbles. Yasmine takes one marble at random from the bag. The probability that she takes a red

marble is 1 in 5. Yasmine returns the marble to the bag and adds five more red marbles to the bag. The probability that she takes one red marble at random is now 1 in 3. How many red marbles were originally in the bag?
Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0
R / (r + g) = 1/5 === 5r = r + g === 4r = g 

<span>(r + 5) / (r + 5 + g) = 1/3 --- 3r + 15 = r + 5 + g </span>
<span>2r = g - 10 ... 4r = 2g - 20 </span>
<span>g = 2g - 20 </span>
<span>g = 20 .... 4r = g ... r = 5 </span>

<span>20 green and 5 red </span>


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\frac{ - 1}{2}

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Cerrena [4.2K]

Answer:

(-4,2)

Step-by-step explanation:

First we have to find a common multiple to use to add and find the system of equations. We need to eliminate one of the variables in order to solve.

Since 5 * 3 = 15, and 3 * -5 = 15, -15x and 15x will cancel each other out. Therefore x will be eliminated.

Before:

5x + 2y = -16

3x + 7y = 2

After:

15x + 6y = -48   <----------Now we solve for y

-15x + -35y = -10

+----------------------

-29y = -58

-29      -29

y = 2

Now what we do is we choose and equation and solve for x, since it is still unknown. Any equation is fine but I will choose the second one since it has easy numbers.

3x + 7y = 2

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10. An arithmetic sequence has this recursive formula. What is the explicit formula?​
Mrrafil [7]

Answer:

a_{n}=45-3n

Step-by-step explanation:

Method 1:

Arithmetic sequence is in the form

a_{n} =a_{1} +(n-1)d\\

d is the common difference, can be found by:

d=a_{n}-a_{n-1}=-3

Subtituting the a_{1} and d

You get:

a_{n}=42+(-3)(n-1)=45-3n

Method 2 (Mathematical induction):

Assume it is in form a_{n}=45-3n

Base step: a_{1} =45-3(1)=42

Inducive hypophesis: a_{n}=45-3n

GIven: a_{n+1} =a_{n}-3

a_{n+1}=45-3n-3=45-3(n+1)

Proved by mathematical induction

a_{n}=45-3n

5 0
3 years ago
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