Answer:
1. -1/28
2. -4
3.A) The attendance increased by an average of 25 people per game from game 2 to game 5.
4. -.125
Step-by-step explanation:
To find the rate of change, we use the formula
f(x2) - f(x1)
--------------
x2-x1
1.
f(x) = -(x) ^ 1/3
f(64) = -(64) ^ 1/3 = -4
f(8) =- (8)^1/3 = -2
f(64) - f(8) -4--2 -4+2 -2 -1
-------------- = --------- = ------------- = ----------- = ------
64 - 8 56 56 56 28
2.
f(2) = 9
f(-2) = 25
f(x2) - f(x1) f(2) - f(-2) 9-25 -16 -16
-------------- =----------- = ----------------- = ---------- = ----------- = -4
x2-x1 2--2 2+2 4 4
3.
f(5) = 755
f(2) = 680
f(x2) - f(x1) f(5) - f(2) 755-680 75
-------------- = ---------- = -------------- = ---------- = 25
x2-x1 5-2 3 3
A) The attendance increased by an average of 25 people per game from game 2 to game 5.
4.
f(-1) = -.25
f(1) = -.5
f(x2) - f(x1) f(1) - f(-1) -.5 --.25 -.5+.25 -.25
-------------- = ---------- = -------------- = ---------- = --------- = -.125
x2-x1 1--1 1+1 2 2
Answer:
15 students do not like either sport
Step-by-step explanation:
See the attached image.
Step 1: put 35 in the "like to play both" (intersection) area.
Step 2: subtract those 35 from the 65 football players. 65 - 35 = 30 players like football but not cricket. Put 35 in the football but not cricket area.
Step 3: subtract 35 from the 55 cricket players. 55 - 35 = 20 players like cricket but not football. Put 20 in the cricket but not football area.
Step 4: Add the 30 + 35 + 20 = 85 together. So 85 players are accounted for as players of one or more sports.
Step 5: 100 - 85 = 15 must be the number of students who did not like either sport. Put 15 in the area outside both circles.
The bacteria would double every 20 minutes, so before then is when the bacteria is still in its singular form before it doubles.
50 / 0.35 =Z
Z=160
Hope it helps!
