Answer:
Answer:
Option (C)
Step-by-step explanation:
Given function is F(x) = x³+ 4x² + x - 6
Possible rational zeros of this function = \frac{\pm1,\pm2,\pm3,\pm6}{\pm1}
±1
±1,±2,±3,±6
[Possible rational zeros of a function f(x) = ax³+ bx² + cx + d,
= \frac{\text{factors of d}}{\text{factors of a}}
factors of a
factors of d
Let the possible zero of this function is 2.
Now do the synthetic division,
2| 1 4 1 -6
↓ 2 12 26
1 6 13 20
Here all the numbers at the bottom are positive by dividing with a positive number 2, therefore, 2 is the upper bound.
There will be no rational zero (Positive) above 2.
Therefore, Option (C) will be the answer.
Answer:
y=12
x=30
Step-by-step explanation:
2x-3y=24 ... 1
x+6y=18 ... 2
2*2:
2x+12y=36...3
3-1:
y=12
x=30
Answer:B
Step-by-step explanation:
Ellen, Joe, Steve, Patty
Answer:
Start by subtracting 3t from both sides of your equation
13t+4=12+3t
-3t. -3t
that gives you
10t+4=12
Subtract 4 from both sides
10t+4=12
-4. -4
That gives you
10t=8
Divide both sides by 10 to leave the variable by itself
10t=8
÷10. ÷10
That leaves you with
t=8/10 or t= 4/5 if you simplify.
Step-by-step explanation: