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NNADVOKAT [17]
2 years ago
13

What is the range of the function y = x^2?

Mathematics
1 answer:
user100 [1]2 years ago
8 0

Answer:

The range is y≥0

Step-by-step explanation:

The shape of this graph is a parabola

You may see this by using the Desmos calculator and typing y=x^2 if you would like to visualize.

(a) The function y = x^2 simply takes whatever number you feed it (x) and outputs x squared.

For example

y = (2)^2=4

y = (3)^2 = 9

(b) To graph x^2 simply make a table of values and plug in 0 -> however high you would like to go ( usually to 5 or so is fine but you could go to infinity).

Example

      y = x^2

                 Y    |     X

                ________

                 2      |   4  

                 3     |   9

                 4    |    16

In this case the function's range is y≥0 because all y values will be greater than or equal to 0.

If you are wanting to learn how to specifically graph this you can look up (Graphing y = x²) if my quick graphing explanation back at mark (b) does not help.

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mafiozo [28]

Answer:

2/9

Step-by-step explanation:

If you meant you want to find U,

1) Divide both side by 2. -> U = 4/9 divided by 2

2) You get U = 4/18, which you can further simplify by dividing 2 on top and bottom to get 2/9

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Besides the definition, what other way can you use the sides of a quadrilateral to prove that that it is a parallelogram? (Site
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3 years ago
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Sladkaya [172]

32 pints is the answer to this question

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gulaghasi [49]

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4 0
3 years ago
Find the coordinates for the midpoint of the segment with endpoints give (3,5) and (-2,0)
Leto [7]

Answer:

The coordinates of the mid-point are :

(\frac{1}{2}, \frac{5}{2})

Step-by-step explanation:

We know that, the coordinates of the mid-point (<em>x</em>, <em>y</em>) of a line segment joining the points (<em>x</em>₁, <em>y</em>₁) and (<em>x</em>₂, <em>y</em>₂) is given by

(x, y) = (\frac{x_{1} +x_{2} }{2},\frac{y_{1}+y_{2} }{2} )

Now, we have the given points as (3, 5) and (-2, 0).

By using the above formula, coordinates of the mid-point (<em>x</em>, <em>y</em>) of the line-segment joining the points (3, 5) and (-2, 0) is given by,

x = \frac{3+(-2)}{2} = \frac{3-2}{2} = \frac{1}{2}

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