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NNADVOKAT [17]
2 years ago
13

What is the range of the function y = x^2?

Mathematics
1 answer:
user100 [1]2 years ago
8 0

Answer:

The range is y≥0

Step-by-step explanation:

The shape of this graph is a parabola

You may see this by using the Desmos calculator and typing y=x^2 if you would like to visualize.

(a) The function y = x^2 simply takes whatever number you feed it (x) and outputs x squared.

For example

y = (2)^2=4

y = (3)^2 = 9

(b) To graph x^2 simply make a table of values and plug in 0 -> however high you would like to go ( usually to 5 or so is fine but you could go to infinity).

Example

      y = x^2

                 Y    |     X

                ________

                 2      |   4  

                 3     |   9

                 4    |    16

In this case the function's range is y≥0 because all y values will be greater than or equal to 0.

If you are wanting to learn how to specifically graph this you can look up (Graphing y = x²) if my quick graphing explanation back at mark (b) does not help.

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Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
Suppose you want to represent a triangle with sides 12 feet, 16 feet, and 18 feet on a drawing where 1 inch = 2 feet. How long s
slega [8]

Answer:

<u>The correct answer is C. 6, 8 and 9 inches.</u>

Step-by-step explanation:

1. Let's review all the information provided for answering the questions properly:

Length of the sides of the triangle = 12 feet, 16 feet and 18 feet.

Scale used : 1 inch = 2 feet.

2. How long should the sides of the triangle be in inches?

For calculating the length of the sides of the triangle in the draw, we use the scale this way:

1st Side = 12 feet

12 feet/2 = 6 inches

2nd Side = 16 feet

16 feet/2 = 8 inches

3rd Side = 18 feet

18 feet/2 = 9 inches

<u>The correct answer is C. 6, 8 and 9 </u>

8 0
3 years ago
Please anyone help i really need help it’s due please!!
Diano4ka-milaya [45]
Answer: w = 41

QU = 2(RT)

w + 41 = 2w
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The denominator is 40
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7/40=0.175
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3 years ago
X/(x-2) + (x-1)/(x+1) = -1 <br><br> How to solve?
kirill115 [55]
Multiply entire equation by (x-2)(x+1) to get rid of the denominators That would lead to X(x+1)+(x-1)(x-2)=-1(x-2)(x+1)
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7 0
3 years ago
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