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alexdok [17]
3 years ago
15

Why do ⅚, 15,18, and 10/12 equal each other?

Mathematics
1 answer:
Burka [1]3 years ago
8 0
10/12 is an un simplified form of 5/6.
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6. What value of a makes this equation true?
arlik [135]
The answer I believe is c
8 0
3 years ago
One side of a square is 10 units. Which is greater, the number of square units for the área of the square or the number of units
ValentinkaMS [17]
The area of the square would be greater. To get the area of a square you need to multiply the length and width of the square, therefore you would multiply 10x10 which comes out to be 100. The perimeter would only be 40.
3 0
3 years ago
Read 2 more answers
A certain electronics manufacturer found that the average cost C C to produce x DVD/Blu- ray players can be found using the equa
Kisachek [45]

Answer:

83,491.67 dollars

Step-by-step explanation:

Given that a certain electronics manufacturer ound that the average cost C C to produce x DVD/Blu- ray players can be found using the equation  C=0.03x^2-5x+700

To find the minimum average cost per machine we can use derivative test.

we find first and second derivative.

If for a particular value of x first derivative is 0 and second derivative is positive, then that x satisfies the minimum cost criteria.

C=0.03x^2-5x+700\\C'(x) = 0.06x-5\\C"(x) = 0.06>0

Second derivative is always positive

I derivative =0 gives

x=5/0.06 \\=83.33\\~83

For 83 players the cost would be minimum

Minimum cost = 0.03(83)^2-5(83)+700\\=491.67

3 0
4 years ago
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
Which of the following is not a correct name for the line above?
BaLLatris [955]

Answer:

Kn

Step-by-step explanation:

We are supposed to represent the line by denoting the same with atleast two points lying on it. Here in B option, the point K lies on the line but n does not. While n in itslef represents a ray. Hence the correct option for this problem is B)

3 0
3 years ago
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