Answer:
![2(x-2)^2-7](https://tex.z-dn.net/?f=2%28x-2%29%5E2-7)
Step-by-step explanation:
![y=2x^2-8x+1](https://tex.z-dn.net/?f=y%3D2x%5E2-8x%2B1)
When comparing to standard form of a parabola: ![ax^2+bx+c](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc)
Vertex form of a parabola is:
, which is what we are trying to convert this quadratic equation into.
To do so, we can start by finding "h" in the original vertex form of a parabola. This can be found by using:
.
Substitute in -8 for b and 2 for a.
![\frac{-(-8)}{2(2)}](https://tex.z-dn.net/?f=%5Cfrac%7B-%28-8%29%7D%7B2%282%29%7D)
Simplify this fraction.
![\frac{8}{4} \rightarrow2](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B4%7D%20%5Crightarrow2)
![\boxed{h=2}](https://tex.z-dn.net/?f=%5Cboxed%7Bh%3D2%7D)
The "h" value is 2. Now we can find the "k" value by substituting in 2 for x into the given quadratic equation.
![y=2(2)^2-8(2)+1](https://tex.z-dn.net/?f=y%3D2%282%29%5E2-8%282%29%2B1)
Simplify.
![y=-7](https://tex.z-dn.net/?f=y%3D-7)
![\boxed{k=-7}](https://tex.z-dn.net/?f=%5Cboxed%7Bk%3D-7%7D)
We have the values of h and k for the original vertex form, so now we can plug these into the original vertex form. We already know a from the beginning (it is 2).
![a(x-h)^2+k\\ \\ 2(x-2)^2-7](https://tex.z-dn.net/?f=a%28x-h%29%5E2%2Bk%5C%5C%20%5C%5C%202%28x-2%29%5E2-7)
A right circular cone has a circle as its base.
All answers that have B = l * w cannot be correct as that is the area of a rectangle, not a circle.
The area of a circle is A = pi r^2, so you need B = pi r^2 in the formula.
The only formula that is correct is choice D. V = 1/3 Bh, where B = pi r^2
The LCM of 15 and 50 is 150
Answer: 4
Step-by-step explanation:
when you replace the variables with their numbers, you would get:
5+3/5-3 =
8/2 =
4
hope this helps lol