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stellarik [79]
3 years ago
12

0.5 kilograms (kg) is equal to how many ounces? Round your answer to the nearest tenth.

Mathematics
2 answers:
enot [183]3 years ago
3 0

Answer:

17.6 ounces per 500 g

Step-by-step explanation:

Knowing one ounce equals 28.34 g, all we have to do is divide half a kilo (500 g) by the equivalent of an ounce to get the number of ounces in a kg.  So,

O = 500 g / 28.34g/ounce = 17.64 ounces

We round that to the nearest tenth... to get 17.6 ounces per 500 g

Converting between metric and imperial/US system is always complicated.

Gwar [14]3 years ago
3 0

Answer:

0.5 kilograms (kg) is equal to 17.6 ounces

Step-by-step explanation:

We have

                    1 kg = 35.274 ounces

                   0.5 kg = 0.5 x 35.274 = 17.637 ounces

Rounding to nearest tenth

              0.5 kg = 17.637 ounces   = 17.64 ounces = 17.6 ounces

So we have 0.5 kilograms (kg) is equal to 17.6 ounces    

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Answer:

24/91

Step-by-step explanation:

6 red socks and 8 black = 14 socks

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3 years ago
What is bigger 2/4 or 1/8
suter [353]

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3 years ago
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In triangle JKL, tan(b°) = three fourths and cos(b°) =four fifths. If triangle JKL is dilated by a scale factor of one half, wha
uysha [10]

The angle of sine has a value of 3/5.

Option A is the correct representation of angle sin(b°).

<h2>How do you calculate the angle b for sine?</h2>

Given that tan(b°) = 3/4 and cos(b°) = 4/5.

In trigonometry, we know that,

\dfrac {sin \theta}{cos \theta} = tan \theta

The angle of sine can be written as below.

sin \theta = cos \theta \times tan \theta

For the angle b, the above expression can be written as,

sin (b^\circ) = cos (b^\circ) \times tan (b^\circ)

Substituting the values in the above expression, we get,

sin (b^\circ) = \dfrac {3}{4} \times \dfrac {4}{5}

sin (b^\circ) = \dfrac {3}{5}

Hence we can conclude that the angle of sine has a value of 3/5.

To know more about the angle of sine, follow the link given below.

brainly.com/question/2512010.

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