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olchik [2.2K]
3 years ago
14

. In the ____, you justify acquiring newer and better resources to investigate computer forensics cases.

Computers and Technology
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

Business Case

Explanation:

In the <u>Business Case</u>, you justify acquiring newer and better resources to investigate computer forensics cases.

You might be interested in
You work in an office that uses Linux and Windows servers. The network uses the IP protocol. You are sitting at a Windows workst
vichka [17]

Answer:

Ping

Explanation:

If working in an environment that uses Linux and Windows servers and the network using IP protocol, if an application you are using is unable to to connect to a windows server named FileSrv2, you will need to test network connectivity between your workstation and the server by using either the "ping" or "traceroute" command.

3 0
3 years ago
It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

5 0
4 years ago
Where does append add the new elements?
ZanzabumX [31]

Answer:

"Option 1: To the end of an array." is the correct answer.

Explanation:

The word "Append" means adding to the end of a document.

Appending means whatever new content is added, it is added at the end of the document or data structure.

Similarly,

Appending an array means adding new elements to the end of the array.

Hence,

"Option 1: To the end of an array." is the correct answer.

7 0
3 years ago
The WITH CHECK OPTION clause _________.a. prevents a row in a view form being updated if that would cause the row to be excluded
Finger [1]

Answer:

The correct answer to the following question will be Option A.

Explanation:

For such a standards-compliant perspective, the WITH CHECK OPTION clause could be provided to prohibit additions to rows under which the select statement WHERE clause is sometimes not valid.

  • This also prevents changes to rows under which the WHERE clause becomes accurate but perhaps the change will result in it not being valid.
  • It helps to prevent updating of a row throughout a view process if this causes the row to still be omitted from those in the display.
5 0
3 years ago
Create a recursive method, a method that calls itself, that returns true or false depending on whether or not a given string is
ICE Princess25 [194]

Answer:

public class CheckPalindrome{

public static boolean IsPalindrome(String str){

if(str.Length<1)

{

return true;

}

else

{

if(str[0]!=str[str.length-1])

return false;

else

return IsPalindrome(str.substring(1,str.Length-2));

}

}

public static void main(string args[])

{

//console.write("checking palindromes");

string input;

boolean flag;

input=Console.ReadLine();

flag= IsPalindrome(input);

if(flag)

{

Console.WriteLine("Received"+input+"is indeed palindrome");

}

else

{

Console.WriteLine("received"+input+"is not a palindrome");

}

}

Explanation:

6 0
3 years ago
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