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FinnZ [79.3K]
3 years ago
11

I WILL GIVE BRAINLIEST Hey can someone tell me simply HOW to come to this conclusion? im a bit confiused as to how, dont want to

cheat i want to learn. (P.S ive missed multiple grades which has left me with alot of gaps to fill.)

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

Option B, x + 2y = 8

Step-by-step explanation:

When two lines are parallel, their gradients are equal i.e M1 = M2

(Note: When two lines are perpendicular, the product of their gradients is equal to - 1 i.e M1M2 = -1)

Gradient of a line = (y2 - y1)/(x2 - x1)

Using coordinates (-4,0) and (4,-4)

Gradient of the line = (-4-0)/[4-(-4)]

= -4/4+4

= -4/8

= -1/2

Therefore gradient of the parallel line is -1/2

Equation of a line using slope intercept form

(y - y1) = m(x - x1)

The parallel line passes through point (2,3)

y - 3 = -1/2 ( x - 2)

2(y - 3) = -1(x - 2)

2y - 6 = -x + 2

2y + x = 8

I hope this helps you to learn....

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irakobra [83]

Answer:

Step-by-step explanation:

1. (2/z)x^2 + (3/z)y^2 is an equation for an ellipse, so the answeris A.

2. We can rewrite this as x^2 + y^2 = 25 - z^2. This is theequation for a circle, so the level curves are circles. However,they are unevenly spaced, because the radius of each circle issqrt(25-z^2). So the answer is F.

3. Rewriting, we have y = z/x. This is the equation of a hyperbola(except when z = 0). So the answer is B.

4. Rewriting, we have x^2 + y^2 = z^2. This is the equation for acircle of radius z, so the level curves are evenly spaced circles.The answer is C.

5. Solving for x, we have x = 1 + 1/z. These level curves arevertical lines, which are obviously parallel. However, they areunequally spaced, since the distance between them gets smaller as zgets larger. The answer is E.

6. x^2 + y^2 = z is the equation for a circle of radius sqrt(z).They are unevenly spaced once again, because the radii do notincrease linearly with z. The answer is F.

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Answer:

FRACTION         DECIMAL                   PERCENT

3/100                   0.03                              3%

3/2                         1.5                                150%

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4 0
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Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 244 meters
MissTica
We know that

[perimeter of rectangle]=2*(<span>length+width)
</span>
Let
x-----------> length
y-----------> width
so
P=2*(x+y)-----------> 244=2*(x+y)-----> x+y=122-------> y=122-x

Area=x*y-------> x*(122-x)----> 122x-x²

find the derivative function and equals to zero

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<span>the maximum area is given by a square
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6 0
3 years ago
Given m∠JML = 80 and m∠KML = 33, what is m∠JMK
Harrizon [31]

Answer:

<h2>47°</h2>

Step-by-step explanation:

Given m∠JML = 80 and m∠KML = 33, to calculate the value of angle m∠JMK, we will apply the formula since all the angles are all acting at point M.

m∠JML = m∠JMK+m∠KML

Substituting the values given into the equation;

80 = m∠JMK + 33

subtract 33 from both sides of the equation

m∠JMK = 80-33

m∠JMK = 47°

<em>Hence the value of angle m∠JMK is 47°</em>

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Step-by-step explanation:

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