Question

Ax4 + bx2 + c=0 (a>0) (c>0)

Answer 1

The quadratic equation has two solutions if b^2 - 4ac > 0

Given the equation ax^4 + bx^2 + c=0

• Let P = x^2

Substitute into the formula to have:

• a(x^2)^2 + bx^2 + c =0

The equation becomes aP^2 + bP + c = 0

For us to have a unique solution, the discriminant b^2 - 4ac must be greater than zero. Hence the quadratic equation has two solutions if b^2 - 4ac > 0

learn more on discriminant here; brainly.com/question/1537997