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faltersainse [42]

2 years ago

6

A file that is 242 megabytes is being downloaded. If the download is 18.7% complete, how many megabytes have been downloaded? Ro

und your answer to the
nearest tenth.

1 answer:

PolarNik [594]2 years ago

5 0

Answer:

45.3 megabytes

Step-by-step explanation:

242 x 18.7%

= 242 x 0.187 = 45.254 = 45.3 megabytes

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Jorden leaves home for school on his bike everyday at 6:00 AM, traveling at 32 km/h. one day he forgot his homework, which his m

densk [106]

Answer:

She caught up with Jordan at 6:39 AM

Step-by-step explanation:

We solve this question making linear functions for the distances that Jorden and his mom have driven, and then we equalize them to find the moment they caught up.

Jorden leaves home for school on his bike everyday at 6:00 AM, traveling at 32 km/h.

Her mom will have left 15 minutes after he left, when he will already have traveled $\frac{15*32}{60} = \frac{32}{4} = 8\text{km}$

So, his position after t minutes can be modeled by the following function:

$J(t) = 8 + 32t$

His mom

His mom goes after him starting from home, so the initial position is 0, with a velocity of 52 km/h. So her position can be modeled by the following function:

$M(t) = 52t$

At what time did she catch up with Jorden,

She catches up t minutes after 6:15 AM.

t is found when

$M(t) = J(t)$

So

$8 + 32t = 52t$

$20t = 8$

$t = \frac{8}{20}$

$t = 0.4$

0.4 of an hour is 0.4*60 = 24 minutes.

So she catched up with Jordan after 6:15 AM + 24 minutes = 6:39 AM

4 0

2 years ago

F (x) = x^2 + 2x - 5<br> g(x) = 2x + 4<br> What is (f• g)(x)?

Vilka [71]

Answer:

Step-by-step explanation:

This is a composite function, f(g(x)). This means, working from the inside function to the outside, we will take the function g and plug it in for x in the f function. g(x) = 2x + 4. We will plug that into f(x) and evaluate f(2x+4):

$f(g(x))=(2x+4)^2+2(2x+4)-5$ and I imagine your teacher has you simplify completely. We FOIL and distribute to get

$f(g(x))=4x^2+16x+16+4x+8-5$ which, by combining like terms, give us

$f(g(x))=4x^2+20x+19$

5 0

3 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are <u>neither</u> parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are <u>parallel</u>

║

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are <u>Neither</u> parallel nor perpendicular

<u>Neither</u>

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are <u>perpendicular</u>

⊥

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are <u>parallel</u>

║

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are <u>neither</u> parallel nor perpendicular

<u>Neither</u>

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

<u>Neither</u>

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is <u>Neither</u>

Learn more here:

brainly.com/question/16732089

6 0

3 years ago

50 POINTS (SUPER IMPORTANT PLEASE HELP)

sergeinik [125]

The answer would be you can’t simplify the first one but the second would be 15 square root 5

Hope this helps

Have a great day/night

Feel free to ask any questions

5 0

2 years ago

Help please with algebra problem

Strike441 [17]

Number of weekend minutes used: x
Number of weekday minutes used: y

This month Nick was billed for 643 minutes:
(1) x+y=643

The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44

We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44

Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y

Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44

Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72

Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243

Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400

Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243

6 0

3 years ago