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Ulleksa [173]
2 years ago
5

An investment, initially worth £645.3, grows at a constant continuous rate of 0.05. After how many years will it be

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
6 0

The investment growth is an illustration of an exponential function.

It will take 78.3 years for the investment to reach £29437.2

The given parameters are:

  • Initial worth: 645.3
  • Rate: 0.05

<h3>Exponential functions</h3>

An exponential function is represented as:

y = a(1 + r)^t

Where:

  • a represents the initial value
  • r represents the rate.

<h3>The number of years</h3>

So, we have:

y = 645.3(1.05)^t

When the investment becomes 29437.2, the equation becomes

29437.2 = 645.3(1.05)^t

Divide both sides by 645.3

45.6=1.05^t

Take the logarithm of both sides

\log(45.6)=\log(1.05)^t

This gives

\log(45.6)=t\log(1.05)

Make t the subject

t = \frac{\log(45.6)}{\log(1.05)}

t = 78.3

Hence, it will take 78.3 years for the investment to reach £29437.2

Read more about exponential functions at:

brainly.com/question/11464095

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