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Anuta_ua [19.1K]
2 years ago
10

Find the approximate area of the composite figure below

Mathematics
1 answer:
Readme [11.4K]2 years ago
3 0
<h3> Δ</h3><h3> <u>E</u><u>X</u><u>A</u><u>M</u><u>P</u><u>L</u><u>E</u></h3>

❤

<h3>I hope i can help</h3>

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1. Two object accumulated a charge of
In-s [12.5K]

Answer:

The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F  =181.274 N

Step-by-step explanation:

As

Two object accumulated a charge of  4.5 μC and another a charge of 2.8  μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8  μC = 2.8 × 10⁻⁶  C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}

   =\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}        ∵ 4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}    ∵ \mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4

\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}

  =\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}

  =\frac{12.6}{0.025^2\times \:35.4\pi }        ∵ \left(10^{-2}\times \:2.5\right)^2=0.025^2

  =\frac{12.6}{0.022125\pi }        ∵ 35.4\pi\times 0.025^2=0.022125\pi

   =\frac{12.6}{0.06950 }

F  =181.274 N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F  =181.274 N

7 0
3 years ago
Solve the following algebraic equation using appropriate
Neko [114]
( x + 1 )/ 3 = x + 2
Multiply 3 on both sides
x + 1 = 3x + 6
Subtract 6 on both sides
x - 5 = 3x
Subtract x from both sides
-5 = 2x
Divide 2 from both sides
x = -2.5
6 0
3 years ago
1000 times 100 in exponent
vampirchik [111]

Answer: 2^5 · 5^5

Hope it helps

7 0
4 years ago
OMG!!??!!?? SCIENTISTS TRANSFORM 6IX9INE INTO A RAT?!??????!!?! LOOK AT HIM!!!!!!!!​
qaws [65]
Wowza that’s crazy!!!!!!!
5 0
3 years ago
Read 2 more answers
Can you help givie full info thanks
liubo4ka [24]

Answer:

13

Step-by-step explanation:

Using long division, you can multiply each given value by 100 to eliminate the decimals:

2.08x100=208

0.16x100=16

OR (calculator method)

2.08÷0.16=13

You must divide the amount of food per cat by the total amount of food available to determine how many cats can be fed.  This division can be done using a calculator.

OR

5 0
2 years ago
Read 2 more answers
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