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masha68 [24]
3 years ago
13

A certain organization wants to know the opinion of the adult residents, 35 years of age or older, of the xxx city with a total

population of 55,000 about lowering the drinking age to 18
Mathematics
1 answer:
DaniilM [7]3 years ago
5 0

0.7 +/- 0.0635 is the answer. The confidence interval is

p±1.96√p(1−p)/n

<span>p = 140/200 = 0.7 (the proportion in favor of lowering the drinking age) n = the sample size, 200 1.96 is the critical value for a 95% confidence interval, from the z-table (standard normal distribution)</span>

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The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.
Tanya [424]

The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

<h3>What is mean, median and mode of a data set?</h3>

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

  • The mean is-

\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5

  • The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

  • The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41   41   43   43   45   50   52   53   54   62   63   63   67   75   97  

  • The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

r=97-41\\r=56

  • The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

IQR=63-23\\IQR=20

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

brainly.com/question/14532771

#SPJ1

4 0
1 year ago
A jar contains 8 red marbles, 5 blue marbles and 3 green marbles. Christopher wins if he picks a red marble and Janet wins if he
Ivenika [448]

Answer:

Yes, the game is fair because Christopher and Janet have an equal probability of winning.

Step-by-step explanation: Christopher - Red marble=8

Janet - blue + green= 5+3= 8

6 0
3 years ago
Tim answered all queston on is math test but got 10 answers wrong. He received 4 points for every corect answer, and there was n
Eduardwww [97]

Answer:

See below in Bold.

Step-by-step explanation:

If he scored 76 points he must have answered 76/4 = 19 questions correctly.

If the total number of questions is q then our equation is q = 10 + 76/4

= 10 + 19 = 29 questions.

6 0
3 years ago
PLZ HELP ITS VERY VERY VERY DUE
bazaltina [42]

Answer:

The desktop computers will cost 2,850 and the notebook computers will cost 4,875 and if someone got n notebooks and d desktops it will cost m money

Step-by-step explanation:

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7 0
2 years ago
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Sorry it's in black and white but i need help with 3a. b. c. and 4
Andrews [41]
It s for a is 20 1in for b it is 36 and for
c

its 50
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3 years ago
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