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Alchen [17]
2 years ago
6

Paul, colin and brian are waiters. One night the restaurant earns tips totalling £77. 40. They share the tips in the ratio 2:3:4

. How much more does brian get over paul?.
SAT
1 answer:
EleoNora [17]2 years ago
6 0

Answer:

$17.20

Explanation:

To easily get the ratio figured out between Paul, Colin and Brian, try seeing how much the ratio adds up to. With 2:3:4, there is a total of 9; so take 1/9th of 77.40 to get $8.60

You can convert these ratios to fractions, with Paul getting 2/9ths, Colin getting 3/9ths and Brian getting 4/9ths

As Brian is effectively getting double the amount of money, you can just take the amount Paul is getting in tips and use that as the reference for how much Brian is earning which is $8.60 x 2 or in this case, $17.20

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marusya05 [52]

The probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade is: D. 0.80.

<h3>How to calculate the probability?</h3>

In this exercise, you're required to determine the probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade. Thus, we would apply Bayes's theorem.

  • Let S represent studied for.
  • Let B represent a score of B or higher grade

Therefore, we need to find P(S|B):

S|B = \frac{B|S \times S}{B|S \times S\; +\; B|S' \times S'} \\\\S|B = \frac{0.55 \times 0.6}{0.55 \times 0.6 \;+ \;0.2 \times 0.4}\\\\S|B =\frac{0.33}{0.33 + 0.08} \\\\S|B =\frac{0.33}{0.41}

S|B = 0.80.

Read more on probability here: brainly.com/question/25870256

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<u>Complete Question:</u>

At the beginning of the semester, a professor tells students that if they study for the tests, then there is a 55% chance they will get a B or higher on the tests. If they do not study, there is a 20% chance that they will get a B or higher on the tests. The professor knows from prior surveys that 60% of students study for the tests. The probabilities are displayed in the tree diagram.

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