The maximum capacitance that can be formed from the given capacitors is 9000.01 μF (in parallel)
<h3>How to find Maximum Capacitance?</h3>
We are given the capacitances as;
3200 μF, 5800 μF, and 0.0100 μF
Now, if the capacitors are in parallel, the equivalent capacitance is;
C_eq = C₁ + C₂ + C₃
Thus;
C_eq = 3200 μF + 5800 μF + 0.0100 μF
C_eq = 9000.01 μF
Now, if the capacitors are in series, the equivalent capacitance is;
1/C_eq = 1/C₁ + 1/C₂ + 1/C₃
Thus;
1/C_eq = (1/3200) μF + (1/5800) μF + (1/0.0100) μF
C_eq = 0.00999995 μF
Therefore the maximum capacitance that can be formed from the given capacitors is 9000.01 μF (in parallel)
Complete question is;
Consider three capacitors, of capacitance 3200 μF, 5800 μF, and 0.0100 μF. What maximum capacitance can you form from these?
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Answer:
Lines AB and CD intersect at E for A (2,4),B (0,2), C (3,0), and D (3,3) on a coordinate plane. Point F is coplanar with these points, but not collinear with AB or CD.
Answer:
Explanation:
cv= standard deviation/ mean
40/3
13.33
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