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2 years ago

PLEASE HELP ACTUALLY WILL MARK BRAINLIEST DONT SEND LINKS!!!

Mathematics

2 answers:

velikii [3]2 years ago

3 0

Answer:

12) 817 19. It becomes

800/20 = 40

13) 3615 72. It becomes

4000/70 = 57.1 = 60

14) 232 64. It becomes

200/60 = 33.3 = 30

15) 559 81. It becomes

600/80 = 7.5 = 8

16) 2986 222. It becomes

3000/200 = 15

17) 10275 232. It becomes

10000/200 = 50

18) 7428 286. It becomes

7000/300 = 23.3 = 20

19) 7143 369. It becomes

7000/400 = 17.5 = 18

20) 628,597 1525, it becomes

600000 - 2000 = 300

Step-by-step explanation:

loris [4]2 years ago

3 0

The answer is 18

hopes this helps

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Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be ac

Likurg_2 [28]

For this problem, the most accurate is to use combinations

Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are $nC_r = \frac{ n! }{r! (n-r)!}$

n represents the amount of things you can choose and choose r from them

You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

$P = \frac{_{117}C_3}{_{120}C_3}$

Where $_{117}C_3$ is the number of ways to select 3 non-defective components from 117 non-defective components and $_{120}C_3$ is the number of ways to select 3 components from 120.

$_{117}C_3 = 260130$

$_{120}C_3 = 280840$

So:

$P = \frac{260130}{280840} = 0.927$

Finally, the probability that at least one of the selected components is defective is:

$P = 1-0.927 = 0.0737$

P = 7.4%

3 0

3 years ago

WHICH IS A TRUE STATEMENT BASED ON THE DOT PLOTS BELOW 10 POINTS

Nata [24]

Answer:

C. Set B has the greater range.

Step-by-step explanation:

We can start out with listing out each set of data in a way that makes it easier to work with.

Set A:

20,20,30,30,40,40,40,40,40,50,50,60,60,60

Set B:

10,10,20,20,20,30,30,30,30,40,50,50,60

We can start by trying to eliminate answer options; starting with D.

To get the mean of a set of data, we need to add all numbers in the data set and then divide by the number of dots on the plot.

For Set B: 10+10+20+20+20+20+30+30+30+30+40+50+50+60=420 then divide by number of dots (14) 420/14=30 The mean of Set B is equal to 30.

Solve the mean for Set A to compare. The mean is 41. D is not true so we can eliminate this answer choice.

We can look at the median of both sets so that we can eliminate answer choice B. The median is the middle most point in the set of data.

Set A median: 40

Set B median: 30

We can eliminate B because it does not have the greater median.

On to option C: range.

To find the range of each data set, we subtract the smallest number from the biggest number.

Set A: 60-20=40

Set B: 60-10= 50

Set B does in fact have a greater range than Set A. Answer choice C is the correct option.

6 0

3 years ago

3.14*16.8*16.8*16.9

vitfil [10]

Answer: 3.14 *16.8*16.8*16.9=14977.3478

14977.3478= 14,977.35

6 0

3 years ago

Football teams toss a coin to see who will get their choice of kicking or receiving to begin a game. the probability that given

Artist 52 [7]

In a toss coin, the only result is a head or a tails. Therefore that ½ of the time you can win or ½ of the time you can lose. Therefore the probability of losing three games in a row is:

<span>Therefore the answer is “True”.</span>

7 0

3 years ago

Read 2 more answers

Jaylon Bedford ordered a combo meal that included 2 hamburgers and a drink. The combo cost $8.50. If the drink is $1.50, how muc

valentinak56 [21]

Answer:

$3.50 each

Step-by-step explanation:

First subtract the drink price from the total,$8.50-$1.50=$7. then divide that amount by 2 since he got 2 burgers. $7/2=$3.50.Each burger is $3.50.

7 0

3 years ago