The picture cannot be dilated to fit the frame. This is because one side of the picture is already 6-inches. So, therefore you cannot dilate the picture to fit the frame.
Answer:
First we need to put all the given information in a table, that way we'll express it better into inequalities.
Cost Production Max.
Console screen (x) $600 450
Wide-screen (y) $900 200
$360,000
We have:

Because they can't spend more than $360,000 in production.

Because the number of television is restricted.
The profit function is
(this is the function we need to maximize).
First, we need to draw each inequality. The image attached shows the region of solution, which has vertices (0,200), (300,200), (450, 100) and (450,0).
Now, we test each point in the profit function to see which one gives the highest profit.
For (300,200):

300 console screen and 200 wide screen give a profit of $77,500.
For (450,100):

450 console screen and 100 wide screen give a profit of $76,250.
<h3>
Therefore, to reach the maximum profits, TeeVee Electronic, Inc., must produce 300 console screen televisions and 200 wide-screen televisions to profit $77,500,</h3>
Answer:
using PEMDAS
Step-by-step explanation:
P parenthesis
E exponents
M multiplication
D division
A addition
S subtraction
Answer:
The elevation lies between -140 and -141.
Step-by-step explanation:
The elevation lies between -140 and -141.
Answer:
h /r = 2.55
Step-by-step explanation:
Area of a can:
Total area of the can = area of (top + bottom) + lateral area
lateral area 2πrh without waste
area of base (considering that you use 2r square) is 4r²
area of bottom ( for same reason ) 4r²
Then Total area = 8r² + 2πrh
Now can volume is 1000 = πr²h h = 1000/πr²
And A(r) = 8r² + 2πr(1000)/πr²
A(r) = 8r² + 2000/r
Taking derivatives both sides
A´(r) = 16 r - 2000/r²
If A´(r) = 0 16 r - 2000/r² = 0
(16r³ - 2000)/ r² = 0 16r³ - 2000 = 0
r³ = 125
r = 5 cm and h = ( 1000)/ πr² h = 1000/ 3.14* 25
h = 12,74 cm
ratio h /r = 12.74/5 h /r = 2.55