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aivan3 [116]
2 years ago
10

Which is a good study tip?

SAT
2 answers:
timofeeve [1]2 years ago
8 0

Answer:when you study all ways write notes this is very important if u type your notes you have a higher chance of forgetting what the notes were and if u write than you will probably not forget

Explanation:

nadezda [96]2 years ago
3 0

Answer:

The most effective practice is to work a short time on each class every day. The total amount of time spent studying will be the same (or less) than one or two marathon library sessions, but you will learn the information more deeply and retain much more for the long term—which will help get you an A on the final.

Explanation:

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Iggohdydufufufciucuccuucucucuccuuccucuucvu
tigry1 [53]

Answer:

Its A.

Explanation:

AP courses provide a highschool credit if you pass the course, but your only granted a college credit if you pass the End of Course Standardized AP Exam with a 3 or higher.

Dual enrollment courses offer an enrollment into an actual college course. So passing the class and a final course exam (if required), will assuredly grant you both a highschool credit and a college credit.

3 0
3 years ago
Read 2 more answers
If |2x - 2| > 2, what is the range of x?
EastWind [94]

Answer:

B is the answer

X < = 0 or x > =2

Explanation:

2x -2 >= 2 or 2x-2 < = - 2

2x > =4 Or 2x < = 0

X > =2. Or x < = 0

7 0
3 years ago
For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an
Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}

where;

  • n = Number of electrons = 2
  • \mathbf{E_o} = Initial voltage = 0.77 V
  • \mathbf{E_{cell}} = Cell voltage = 0.78 V
  • \mathbf{[Mn^{2+}]} = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}

\mathbf{Fe^{2+} =0.02297 \ M }

Learn more about using the Nernst equation here:

brainly.com/question/24258023

6 0
2 years ago
PLEASE HELP I WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!!!!
alexandr402 [8]

the answer is D good job  

7 0
3 years ago
Read 2 more answers
Bakugou needs help
Anvisha [2.4K]

Answer:

B

Explanation:

4 0
4 years ago
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