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2 years ago

Please help!! markup and markdown word problems.

Mathematics

1 answer:

Zina [86]2 years ago

5 0

The new price of the scooter will be:

= $50 - (20% × $50)

= $50 - $10

= $40

The sale price of the football will be:

= 35% × $60

= $21

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What is the range of y=3sin(x)?

den301095 [7]

Answer:

The range is -3≤y≤3 - 3≤y≤3.

Step-by-step explanation:

I hope this helps! :)

6 0

2 years ago

Why was igor unhappy about his spelling test even though he got every thing right

Furkat [3]

Igor might've been unhappy because he cheated to get a good grade/score.

4 0

3 years ago

Read 2 more answers

A 55m and 35m broad park is surrounded by a 2.5m wide path.

daser333 [38]

Step-by-step explanation:

☄ $\underline {\underline{ \text{Given}}} :$

Length of a park ( l ) = 55 m
Breadth of a park ( b ) = 35 m
Width running outside the park ( d ) = 2.5 m
Rate of paving the path with stones = Rs 120 per sq.metre

☄ $\underline{ \underline{ \text{To \: find}}}:$

Area of the park
Cosy of paving the path with stones at Rs 130 per sq.metre

☄ $\underline{ \underline{ \text{Solution}}} :$

Part 1 : $\boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}$

plug the known values and simplify :

⟹ $\sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}$

⟹ $\sf{5 \times 95}$

⟹ $\sf{475 \: {m}^{2} }$

Part 2 : $\boxed{ \sf{Total \: cost = Area \: of \: paths \: \times Rate}}$

⟹ $\sf{475 \times 120}$

⟹ $\sf{Rs \: 57000}$

$\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \: {m}^{2} \: and \: (ii ) = Rs \: 57000}}}}}$

Hope I helped ! ♡

Have a wonderful day /night ツ

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7 0

3 years ago

What is 5 times a number ,r, decreased by seven

Lapatulllka [165]

Answer:

5n - 7 < 23

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Pls help pls helppp i will giving breanlist

GaryK [48]

Answer:

[-5, 4) ∪ (4, ∞)

Step-by-step explanation:

Given functions:

$f(x)=\dfrac{1}{x-3}$

$g(x)=\sqrt{x+5}$

Composite function:

$\begin{aligned}(f\:o\:g)(x)&=f[g(x)]\\ & =\dfrac{1}{\sqrt{x+5}-3} \end{aligned}$

Domain: input values (x-values)

For $(f\:o\:g)(x)$ to be defined:

$x+5\geq 0 \implies x\geq -5$

$\sqrt{x+5}\neq 3 \implies x\neq 4$

Therefore, $-5\leq x < 4$ and $x > 4$

⇒ [-5, 4) ∪ (4, ∞)

3 0

2 years ago